Question

Brent’s after-school game club has 12 members from which a six-member team is created. Miguel’s after-school sports club has 10 members from which a six-member team is created. Which student’s club has more possible combinations for his six-member team? Brent’s club has more possible team combinations because he has fewer members on each team than Miguel’s does. Brent’s club has more possible team combinations because there are more members to choose from. Miguel’s club has more possible team combinations because there are fewer members in his club. Miguel’s club has more possible team combinations because he has more members on each team than Brent does.

Answer 1

Answer:

Brent’s club has more possible team combinations because there are more members to choose from

Step-by-step explanation:

Brents club can be created in C12 6 =12!/6!/6!=7*8*9*10*11*12/(2*3*4*5*6)=

=924 variants

Miguel's  club can be created in C10 6=10!/6!/4!=7*8*9*10/(2*3*4)=210 variants

924>210 so Brent’s club has more possible team combinations because there are more members to choose from