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allochka39001 [22]
3 years ago
10

Add 2f+5g+7h and 3f+6g+8h

Mathematics
2 answers:
Kruka [31]3 years ago
6 0
5f+11g+15h



Explanation:

2f+5g+7h+3f+6g+8h

You just combine the like terms
5f+11g+15h
tester [92]3 years ago
3 0

Answer:

Step-by-step explanation:

Add the like terms

5f+11g+15h

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Consider the algebraic expression:
GrogVix [38]
Coefficients are the numbers that are next to a variable(a letter in an expression). Therefore the coefficients would be 7 and 18 because they are both next to a variable (y and x).

I can’t exactly remember what a constant is but I think it is a number alone (not next to any variables) and they are ONLY separated by + and - not multiplication or division. In this case it would be all of the numbers that are in between the + or - (all of them.)

I also think a constant could be the variable next to the coefficient. Which would be y and x (next to 7 and 18).

I’m am so sorry I can’t remember what a constant is but I hope the coefficient helps:)
7 0
4 years ago
Read 2 more answers
Solve for x in the equation 3x^2 + 17x + 4 = -6
Sever21 [200]
Subtract -6 from both sides
3x^2 + 17x + 4 - (-6) = -6 - (-6)
3x^2 + 17x + 10 = 0

factor left side of equation
(3x+2)(x+5)=0

set factors to 0
x = -2/3 OR x = -5

I would go with -5
6 0
4 years ago
Read 2 more answers
Any help would be appreciated. Thank you
Anestetic [448]
14-3^2 x (-2)
=14-9 x (-2)
=14- (-18)
=32
5 0
3 years ago
Find the midpoint of the segment with the following end points (10,5) and (6,9)
Taya2010 [7]

Answer:

The mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)

Step-by-step explanation:

Let (x, y) be the mid-point

Given the points

  • (10,5)
  • (6,9)

Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here:

\left(x_1,\:y_1\right)=\left(10,\:5\right),\:\left(x_2,\:y_2\right)=\left(6,\:9\right)

Thus,

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x,\:y\right)=\left(\frac{6+10}{2},\:\frac{9+5}{2}\right)

\left(x,\:y\right)=\left(8,\:7\right)

Therefore, the mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)
3 0
3 years ago
Write a sine function that has a midline of 5, an amplitude of 4 and a period of 3pi/2
soldi70 [24.7K]

Answer:

Step-by-step explanation:

The standard form for this function is

y = Asin(Bx - C) + D where

A is the amplitude,

B is used to find the period in the formula period=\frac{2\pi}{B},

C is used to find the phase shift in the formula ps=\frac{C}{B},

and D is the midline which either moves the function up or down from its natural midline of 0.

We have no given phase shift, so there is no C value. The amplitude is easy; we just fill in A as 4. The period is another story:

\frac{3\pi}{2} =\frac{2\pi}{B} and we solve for B by cross multiplying:

3πB = 4π and

B=\frac{4\pi}{3\pi} so

B = \frac{4}{3} so the function is

y=4sin(\frac{4}{3}x)+5

8 0
3 years ago
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