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Maslowich
2 years ago
10

Solve for X and Y using substitution. 1) 12x +y = 36 x+4y=24

Mathematics
1 answer:
vovikov84 [41]2 years ago
8 0
{x,y}={24,12} I think that is the answer to this question....
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Mr. Darcy could knit 4 ugly sweaters in 100 minutes. How long will it take him to knit 6 ugly holiday sweaters
Nostrana [21]
If you divide 100 by 4 which equals 25 that would be 25mins for one ugly sweater
If you times by 2 that equals 50
If 6=4+2 then you add 100 and 50 together which makes 150.

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HELP PLEASE LOOK AT PICTURE
solniwko [45]

Answer:

It decreases.

Step-by-step explanation:

10 / d

Lets say that it was 10 / 40, which is 10 divided by 40, 0.25.

Now, it has increased to twice the amount of that.

1 / 80, 10 divided by 80, which is 0.125

So, it decreases.

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I'm struggling right now because I learned this but I completely forgot how to do it. I need to find the distance between two po
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3 0
2 years ago
Step by step explanation thanks
Inessa [10]

Answer:

C= 7y +150

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7 0
3 years ago
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Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu
Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

f(x,y_1,{y_1}',{y_1}'')=0
f(x,y_2,{y_2}',{y_2}'')=0

Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

So if we suppose

f(x,y,y',y'')=y''+xy'-y=0

then substituting y=y_2 would give

6x+x(3x^2)-x^3=6x+2x^3\neq0

To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y

Then if y=y_1+y_2, we get

-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0

as desired. So one possible ODE would be

-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0

(See "Euler-Cauchy equation" for more info)
6 0
3 years ago
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