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vladimir2022 [97]
3 years ago
7

Oliver is driving 360 miles,which is 136 miles less than twice the distance Matt is driving. write an equation that can be used

to determine the distance in miles Matt is driving.
Mathematics
1 answer:
Minchanka [31]3 years ago
7 0
The answer would be (2x-136)=360
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1. what would the effect have been on the calculated formula weight ([9] above) of your unknown as compared to the true formula
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If the solution is blue-green, this indicates that some copper is still present in the solution and that not all of it has precipitated. Expect it to be too low because you will have less mass.

With very few exceptions, all copper(I) (cuprous) compounds are diamagnetic and colorless. Cu2O, Cu2Cl2, and cuprous sulfide are a few of the significant commercial compounds of copper(I) (Cu2S).

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Radioactive Decay:
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The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

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Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

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2 1/8 of 450 with solution
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Answer:

Step-by-step explanation:

hello :

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