Question

Using first principal find the gradient of the curve whose equation is y=x^5. show working pleas​

Answer 1

Answer:

The gradient of $y = x^{5}$ is $\frac{dy}{dx} = 5\cdot x^{4}$.

Step-by-step explanation:

Geometrically speaking, the gradient of a curve is the slope of the tangent line at a given point of the curve. From perspective of Differential Calculus, the gradient is the first derivative of the curve. Let $y = x^{5}$, then the gradient of the curve is:

$\frac{dy}{dx} = 5\cdot x^{4}$ (1)

The gradient of $y = x^{5}$ is $\frac{dy}{dx} = 5\cdot x^{4}$.