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larisa86 [58]
3 years ago
13

On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const

ant rate from 20 m/s to a complete stop over a 10 second interval. how does the distance traveled by the truck compare to that of the car?
Mathematics
1 answer:
KIM [24]3 years ago
7 0
To determine the total distance traveled by an object in constant speed, just multiply the speed by the time. So, for the car, the total distance traveled is,
                               distance by car = (20 m/s)(5s) = 100 m
For decelerating object, the distance traveled is,
                          distance = Vt - (at^2)/2
For the truck,
         distance by truck = (20 m/s)(10s) - (2m/s^2)((10s)^2)/2 = 100 m

Relatively, both have traveled the same distance. 
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Angles 1 and 8 are congruent, because they are alternate exterior angles

16.
m = y2 - y1 / x2 - x1
m = 7 - 2 / 4 - 5
m = 5 / -1
m = -5

17.
m = 3 - 3 / 7 - (-5)
m = 0 / 12
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m = 1 - (-2) / 5 - (-4)
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A = (0, 3) - B = (3,0)
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20.
E = (1, 2) - F = (0, 0)
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m = -2 / -1
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Neither, because the slopes are different.

21.
I = (0, 1) - J = (2, -4)
m = -4 - 1 / 2 - 0
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Angle 2 is congruent to angle 1 because of the alternate exterior angle theorem.
Angle 1 is congruent to angle 3 because of the vertical angle theorem.
Angle 2 is congruent to angle 3 because of substitution.
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