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larisa86 [58]
3 years ago
13

On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const

ant rate from 20 m/s to a complete stop over a 10 second interval. how does the distance traveled by the truck compare to that of the car?
Mathematics
1 answer:
KIM [24]3 years ago
7 0
To determine the total distance traveled by an object in constant speed, just multiply the speed by the time. So, for the car, the total distance traveled is,
                               distance by car = (20 m/s)(5s) = 100 m
For decelerating object, the distance traveled is,
                          distance = Vt - (at^2)/2
For the truck,
         distance by truck = (20 m/s)(10s) - (2m/s^2)((10s)^2)/2 = 100 m

Relatively, both have traveled the same distance. 
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A cookie recipe states for every 3 cups of flour, 1.5 teaspoons of vanilla are
guapka [62]

Answer:

2.5 Teaspoons of vanilla are needed.

Step-by-step explanation:

If 3 cups of flour is 1.5 teaspoons of vanilla. 1.5 /3=.5 Meaning there is .5 teaspoons of vanilla per cup of flour.

If you have 5 cups of flour   5 x .5= 2.5 (teaspoons)

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3 years ago
Identify the constant of proportionality
Sveta_85 [38]

Answer:

When two variables are directly or indirectly proportional to each other, then their relationship can be described as y = kx or y = k/x, where k determines how the two variables are related to one another.

Step-by-step explanation:

This k is known as the constant of proportionality.

3 0
3 years ago
1 2 3 4 5 6 7 8 9 10 Susan plans to use 120 feet of fencing to enclose a rectangular area for a garden. Which equation best mode
Troyanec [42]

Answer:

Area = 60x - x^2

Step-by-step explanation:

Given

Perimeter = 120

Side\ 1 = x

Required

The area of the garden

First, we calculate the length of the other side using:

Perimeter = 2 *(Side\ 1 + Side\ 2)

This gives:

120 = 2 *(x + Side\ 2)

Divide both sides by 2

60 = x + Side\ 2

Make Side 2 the subject

Side\ 2 = 60 - x

So, the area of the garden is:

Area = Side\ 1 * Side\ 2

Area = x * (60 - x)

Expand

Area = 60x - x^2

7 0
2 years ago
Question 2 -of 15 Step 1 of 1No Time LimitA company manufactures two products. One requires 5 hours of labor, 3 poundsof raw mat
elena-14-01-66 [18.8K]

the cost of labour per hour is $7.20

the cost of raw materials per pound is $11.60

Explanation:

For product one:

time = 5 hours of labour

let the cost labour per hour = x

Amount = 3 pounds of raw amterials

let the cost of one pound raw material = y

Cost to produce each product = $70.8

The equation:

time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product

5(x) + 3(y) = 70.80

5x+3y=70.8....\mleft(1\mright)

For product 2:

time = 3.5 hours of labour

let the cost of labour per hour = x

Amount = 13 pounds of raw amterials

let the cost of one pound raw material = y

Cost to produce each product = $176.00

The equation:

time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product

3.5(x) + 13(y) = 176

3.5x+13y=176\text{   .... (2)}

combining both equations:

5x + 3y = 70.8 ...(1)

3.5x + 13y = 176 ....(2)

Using elimination method:

To eliminate y, we will multiply equation (1) by 13 and equation (2) by 3 so that both coefficient of y become the same

65x + 39y = 920.4 ...(*1)

10.5x + 39y = 528 ...(2*)

subtract equation (2*) from (1*):

65x - 10.5x + 39y - 39y = 920.4 - 528

54.5x + 0 = 392.4

54.5x = 392.4

divide both sides by 54.5:

x = 392.4/54.5

x = 7.2

substitute for x in any of the equations

Using equation 1: 5x + 3y = 70.8

\begin{gathered} 5\mleft(7.2\mright)+3y=\text{ 70.8} \\ 36\text{ + 3y = 70.8} \\ 3y\text{ = 70.8 - 36} \\ 3y\text{ = 34.8} \\  \\ \text{divide both sides by 3:} \\ \frac{3y}{3}=\frac{34.8}{3} \\ y\text{ = }11.6 \end{gathered}

Hence, the cost of labour per hour is $7.20 and the cost of raw materials per pound is $11.60

6 0
1 year ago
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