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3 years ago

Please help this is Geometry

Mathematics

1 answer:

Vikentia [17]3 years ago

6 0

Answer:

solution given:

volume of lower one[V1]=l×b×h=1.5×0.5×0.5=0.378m³

volume of upper one [V2]=l×b×h=1×0.5×(0.75-0.5)=

0.125m³

total volume=V1+V2=0.378m³+0.125m³=0.503m³

0.503m³ is your answer

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<u>Solution:</u>

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To check how many solutions are there for system of equations $a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0$ , we need to compare ratios of $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}$

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