Answer:
9x(3x-2) (3x+2)
Step-by-step explanation:
![81x^{3}-36x](https://tex.z-dn.net/?f=81x%5E%7B3%7D-36x)
9(9x³ - 4x)
9x(9x² - 4)
Since both terms are perfect squares factor using the difference of squares formula, a² - b² = (a + b) (a - b)
Therefore, 9x(3x-2) (3x+2)
Answer:
3·2 - 3·b = 6 - 3b
Step-by-step explanation:
You "distribute" the 3 over the 2 and the -b.
Answer:
![P(A) = \frac{3}{10}](https://tex.z-dn.net/?f=P%28A%29%20%3D%20%5Cfrac%7B3%7D%7B10%7D)
Step-by-step explanation:
Given
![S = \{11,12,13,14,15,16,17,18,19,20\}](https://tex.z-dn.net/?f=S%20%3D%20%5C%7B11%2C12%2C13%2C14%2C15%2C16%2C17%2C18%2C19%2C20%5C%7D)
Required
The probability of having a multiple of 3
Let the event of having a multiple of 3 be represented as: A
So:
![A = \{12,15,18\}](https://tex.z-dn.net/?f=A%20%3D%20%5C%7B12%2C15%2C18%5C%7D)
![n(A) = 3](https://tex.z-dn.net/?f=n%28A%29%20%3D%203)
So, the probability is:
![P(A) = \frac{n(A)}{n(S)}](https://tex.z-dn.net/?f=P%28A%29%20%3D%20%5Cfrac%7Bn%28A%29%7D%7Bn%28S%29%7D)
Where
i.e. the sample size
So:
![P(A) = \frac{n(A)}{n(S)}](https://tex.z-dn.net/?f=P%28A%29%20%3D%20%5Cfrac%7Bn%28A%29%7D%7Bn%28S%29%7D)
![P(A) = \frac{3}{10}](https://tex.z-dn.net/?f=P%28A%29%20%3D%20%5Cfrac%7B3%7D%7B10%7D)
Answer:
1/64
0.015625
Step-by-step explanation:
1/2 * 1/2 = 1/4
1/2 * 1/2 = 1/4
1/2 * 1/2 = 1/4
1/4 * 1/4 = 1/16
1/16 * 1/4 = 1/64
Log₂(6x) - log₂(√x) = 2
log₂[6x/√x] = 2, let's rewrite it in terms of exponent:
(remember : ㏒₂(x) = a (in exponential form) → x = 2ᵃ
6x/√x = 2²
6x/√x = 4, square both sides:
36x²/x = 16 .Simplify:
36x = 16 and x = 16/36 . So x = 4/9