All categories

3 years ago

Plz help asasp it would be appreciated

Mathematics

2 answers:

Reil [10]3 years ago

7 0

Answer:

6x+10y=1060

6= the cost of tickets bought before the dance

x=the number of tickets bought before the dance

10= the cost of tickets bought at the doors

y= the number of tickets bought at the door

1060= total amount of money made from selling tickets

Sidana [21]3 years ago

4 0

This will be your answer

You might be interested in

Can someone plz help? It's algebra, and if you cant help, plz don't answer.

skelet666 [1.2K]

Answer:The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is solid and goes through the points negative 3, 0, negative 4, negative 1 and is shaded in below the line. The other line is solid, and goes through the points 1, 1, 2, negative 1 and is shaded in below the line

Step-by-step explanation:y ≤ −2x + 3 y ≤ x + 3 y ≥ −2x + 3 y ≥ x + 3 y ≤ −3x + 2 y ≤ −x + 2 y > −2x + 3 y > x + 3

3 0

3 years ago

Read 2 more answers

PLS HELP ASAP WILL GIVE BRAINLEAST

Ymorist [56]

Answer:

Step-by-step explanation:

8 0

3 years ago

Cameron earns $7 per hour. How much does he earn in 5 hours

ANEK [815]

All you have to do is multiply both

5 0

4 years ago

Simply (6^5/7^3) ^2

Sav [38]

$\bf \left( \cfrac{6^5}{7^3} \right)^2\implies \left( \cfrac{6^{5\cdot 2}}{7^{3\cdot 2}} \right)\implies \cfrac{6^{10}}{7^6}\implies \cfrac{60466176}{117649}\implies 513\frac{112239}{117649}$

5 0

3 years ago

fatima claims that the distribution of u is uniform with a median of 0.4 field goal percentage. is fatima’s claim supported by t

Amanda [17]

Fatima's claim is not supported by the table because, the distribution is skewed right, with a median of 0.4 field goal advantage.

From the table, the median position is calculated as:

$\mathbf{Median = \frac{1}{5} th}$

$\mathbf{Median = 0.2\ nd }$

The 0.2nd data falls in the 0.4 field goal category.

So, the median element is:

$\mathbf{Median = 0.4}$

However, the distribution of the table are concentrated on the left.

This means that, the distribution is not uniform, instead it is skewed right.

A uniform distribution has a skewness of 0.

Hence, Fatima's claim is not supported by the table