5A + 7 = 3A + 7 + 2A
We need to solve for A.

3A + 7 + 2A = 3A + 2A + 7 = 5A + 7 (We can add 3A and 2A because it's the same variable, so we add the coefficients)

5A + 7 = 3A + 7 + 2A
5A + 7 = 5A + 7

5A + 7 is always equal to 5A + 7 because it's the same equation. So the equation got infinitely many solutions.

4 0

3 years ago

If sin F = 3/5 , what is cos G ?

alukav5142 [94]

Answer:

Step-by-step explanation:

side HG is 3

side FG is 5 hypotenuse

sin F = 3/5 = opposite/hypotenuse

cos G is adjacent/hypotenuse

adjacent side is HG which = 3

hypotenuse is 5

3 0

3 years ago

A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard

Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

$\sigma=\frac{0.8}{\sqrt{37}}=0.13$

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69$

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, $P(z > 1.69) = 1 - P(z < 1.69)$

$P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%$

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0

3 years ago