Answer:
The frequency of oranges is the classroom is 47.37%.
Step-by-step explanation:
The relative frequency of oranges is the number of oranges divided by the total number of fruits.
We have that:
8 students brought 2 apples each. So there are 8*2 = 16 apples
4 students brought an apple and an orange each. So there are 16 + 4*1 = 20 apples and 4*1 = 4 oranges.
7 students brough 2 oranges each. So there are 4 + 2*7 = 18 oranges.
There are 18 oranges, and 20+18 = 38 fruits in total.
So the frequency of oranges in the classrom is

Answer:
3 and 4 not congruent
Step-by-step explanation:
Congruent angles of what... be more specific please..
Answer:
Flying squirrel have to glide is for 9.8 meters approximately.
Step-by-step explanation:
Here we can use Pythagoras theorem.
Height is 9 , base is 4.
We need to find the hypotenuse measure.
So, let's use Pythagoras theorem 
Plug in a as 9 and b 4.

Simplify the left side of the equation


Take square root on both sides.
c=9.8 meters.
Answer: it will trave 56.89 meters before coming to rest.
Step-by-step explanation:
This is a geometric progression since the distance travelled (height) by the ball is reducing by a constant ratio, r. Since the number of times that the ball will bounce is infinite, then we would apply the formula for determining the sum of the terms in a geometric progression to infinity which is expressed as
S = a/(1 - r)
where
S = sum of the distance travelled by the ball
a = initial distance or height of the ball
r = common ratio
From the information given,
a = 128/9
r = (32/3)/(128/9) = 0.75
Therefore,
S = (128/9)/(1 - 0.75) = 56.89 meters