Answer:
11.67
Step-by-step explanation:
Answer:
see attached
Step-by-step explanation:
Domain: -∞, <span>∞
range: -5,</span><span>∞
(the commas mean through; ex.; -5,</span><span>∞..... that means negative 5 thru infinity)</span>
Looks like you just evaluated the summand for the given value of

, whereas the question is asking you to find the value of the sum for the first

terms.
Let

. Then

is the

th partial sum.

happens to be the first term in the series, which is why that box is marked correct:

But the next partial sum is not correct:

and this is not the same notion as the second term (which indeed is 0.75) in the series.
The table models an exponential relationship, and the equation of the table is 
<h3>How to analyze the table of values?</h3>
The table of values is given as:
x 0 1 2 3 4
y 4 2 1 1/2 1/4
The above table shows an exponential model
An exponential model is represented as:

When x = 0 and y = 4, we have

Evaluate
a = 4
When x = 1 and y = 2, we have

Evaluate

Substitute 4 for a
4b = 2
Divide both sides by 4
b = 1/2
Substitute 4 for a and 1/2 for b in 

Hence, the equation of the table is 
Read more about exponential models at:
brainly.com/question/11464095
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