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klemol [59]
3 years ago
15

Would it be division or multiplication

Mathematics
2 answers:
BigorU [14]3 years ago
6 0
It would be division
miv72 [106K]3 years ago
5 0
In this situation, you would use division because when you divide the number of blankets by the number of boxes, you will get how many blankets were put into each kennel. And since there were 1,110 puppy blankets and 27 boxes, divide 1,110 by 27. This will get you the answer 41. This means that there are 41 puppy blankets in each box, and so the answer is D. 41.
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What is the slope of a line perpendicular to the line whose equation is x + 2y =8.
Mademuasel [1]

Answer:

2

Step-by-step explanation:

First, put the line into y = mx + b form to find the slope (m)

x + 2y = 8

Subtract x from both sides

2y = -x + 8

Divide each side by 2

y = -1/2x + 4

So, the slope of this line is -1/2

Perpendicular lines have a opposite reciprocal slope, so the slope of a perpendicular line will be 2.

6 0
3 years ago
What is the diameter of a circle if the circumference is 11?​
Gennadij [26K]

Answer:

d≈3.5

Step-by-step explanation:

d= C/π =11/π≈3.50141

Brainliest plz

7 0
4 years ago
Some help me with these two questions please!!!!!!!
Hatshy [7]

Answer:

I believe #20. is A

Step-by-step explanation:

because if you use distributive property and multiply the 5 to the () numbers you  will get your original question.

Also, i cant see all of the options for #21.

8 0
3 years ago
PLS HELP ASAP I SUCK AT THIS PLSS
Ilia_Sergeevich [38]

Answer:

60

Step-by-step explanation:

60*0.45=27

5 0
3 years ago
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
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