The inverse of the function f(x) = 4(x-3)² + 2 is
The given function is:
f(x) = 4(x - 3)² + 2
To find the inverse of the function:
Make x as the subject of the formula
Replace x by and replace f(x) by x
Therefore, the inverse of the function is:
Learn more here: brainly.com/question/17285960
Looks like .
The latter two critical points occur outside of since
so we ignore those points.
The Hessian matrix for this function is
The value of its determinant at (0, 0) is , which means a minimum occurs at the point, and we have
.
Now consider each boundary:
which has 3 extreme values over the interval of 31/4 = 7.75 at the point (1, 1/2); 8 at (1, 1); and 10 at (1, -1).
and we get the same extrema as in the previous case: 8 at (-1, 1), and 10 at (-1, -1).
which doesn't tell us about anything we don't already know (namely that 8 is an extreme value).
which has 3 extreme values, but the previous cases already include them.
Hence has absolute maxima of 10 at the points (1, -1) and (-1, -1) and an absolute minimum of 0 at (0, 0).