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disa [49]
3 years ago
12

With an 18% discount, Joan was able to save $13.23 for a coat. What was the original price of the coat?

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0
Hi there!

First we need to realise that the 18% discount equals John's savings. Therefore 18% of the original price is $13.23.

When we know 18% of the price, we can also find 1% of the total price.

18% = $13.23
Divide both sides by 18.

1% = $0.735
To find the total price, which equals 100%, we know only need to multiply both sides by 100.

100% = $73.50.
Therefore, the original price for the coat is $73.50.

~ Hope this helps you!
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Answer:

96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is  [335.89 , 356.10].

Step-by-step explanation:

We are given that a group of researchers at the BYU Off-Campus Housing department want to estimate the mean monthly rent that unmarried BYU students paid during winter 2018.

During March 2018, they randomly sampled 314 BYU students and found that on average, students paid $346 for rent with a standard deviation of $86.

So, the pivotal quantity for 95% confidence interval for the average age is given by;

           P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = average rent paid by 314 BYU students = $346

            s = sample standard deviation = $86

            n = sample of students = 314

            \mu = population mean monthly rent of all unmarried BYU students

So, 96% confidence interval for the population mean monthly rent, \mu is ;

P(-2.082 < t_3_1_3 < 2.082) = 0.96

P(-2.082 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.082) = 0.96

P( -2.082 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.082 \times {\frac{s}{\sqrt{n} } } ) = 0.96

P( \bar X -2.082 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X +2.082 \times {\frac{s}{\sqrt{n} } } ) = 0.96

96% confidence interval for \mu = [ \bar X -2.082 \times {\frac{s}{\sqrt{n} } } , \bar X +2.082 \times {\frac{s}{\sqrt{n} } } ]

                                                = [ 346 -2.082 \times {\frac{86}{\sqrt{314} } } , 346 +2.082 \times {\frac{86}{\sqrt{314} } } ]

                                                = [335.89 , 356.10]

Therefore, 96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

5 0
3 years ago
Please help I really need your help
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Answer:

1.  1200 \ kg/m^3

2.

a)

35 cm = 0.35 meters

11 dm = 1.1 meters

15 mm = 0.015 meters

b)

Volume = 0.005775 cubic meters

Mass = 15.5925 kilograms

Step-by-step explanation:

1.

We know

Density = Mass/Volume

Given

Mass = 90 kg

Volume = 0.075 cubic meters

The SI unit for density is kilograms per cubic meters. Our dimensions are just that, so we just need to plug in the numbers into the formula and get our answer. Shown below:

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2.

a)

We need to express 35cm, 11dm, and 15mm in meters

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b)

Volume of the Slab is length * width * height, in meters, that would be:

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THe mass would be found by the formula:

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2700 = Mass/0.005775

Mass = 0.005775 * 2700 =  15.5925 kilograms

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Answer:

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