All categories

2 years ago

Please help will give 50points

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

3 0

Answer:

its 10...

Step-by-step explanation:

You might be interested in

If f(x)=(2x^2)-1, find:<br> -f(3x-1)+2

Sergeeva-Olga [200]

Answer:

-f(3x - 1) + 2 = -18x² + 12x + 1

Step-by-step explanation:

Step 1: Find f(3x - 1)

f(3x - 1) = 2(3x - 1)² - 1

f(3x - 1) = 2(9x² - 6x + 1) - 1

f(3x - 1) = 18x² - 12x + 2 - 1

f(3x - 1) = 18x² - 12x + 1

Step 2: Plug in f(3x - 1)

-(18x² - 12x + 1) + 2

Step 3: Evaluate

-18x² + 12x - 1 + 2

-f(3x - 1) + 2 = -18x² + 12x + 1

8 0

2 years ago

Read 2 more answers

1 (66 divided by 6)+31"

Juliette [100K]

Answer:

1. 42

2. 6

3. 18

4. 0

5. - 2

Step-by-step explanation:

Use BIDMAS

6 0

2 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

A man ran 20 miles in 2 hours. Calculate the average time that it took the man to run each mile in minutes.

konstantin123 [22]

Answer:

he ran 3 miles in 8 mins

Step-by-step explanation:

3 0

2 years ago

Find y'' if y= 9csc x

sineoko [7]

Answer:

y" = csc(x)[9cot²(x) - csc²(x)]

Step-by-step explanation:

Step 1: Define

y = 9csc(x)

Step 2: Find 1st derivative

y' = -9csc(x)cot(x)

Step 3: Find 2nd derivative

y" = 9csc(x)cot(x)cot(x) + -csc(x)csc²(x)

y" = 9csc(x)cot²(x) - csc³(x)

y" = csc(x)[9cot²(x) - csc²(x)]

4 0

3 years ago