Answer:
![\bar X = \frac{2276}{48}=47.417](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20%5Cfrac%7B2276%7D%7B48%7D%3D47.417)
If we compare this value with the 47.3 proposed we have the following error
![Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%](https://tex.z-dn.net/?f=%20Error%20%3D%20%5Cfrac%7B%7CActual-real%7C%7D%7Breal%7D%2A100%20%3D%20%5Cfrac%7B%7C47.417-47.3%7C%7D%7B47.3%7D%2A100%20%3D0.247%5C%25)
The computed mean is close to the actual mean because the difference between the means is less than 5%.
Step-by-step explanation:
Assuming the following dataset:
Speed 42-45 46-49 50-53 54-57 58-61
Freq. 21 15 6 4 2
And we are interested in find the mean, since we have grouped data the formula for the mean is given by:
![\bar X = \frac{\sum_{i=1}^n x_i f_i}{\sum_{i=1}^n f_i}](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20x_i%20f_i%7D%7B%5Csum_%7Bi%3D1%7D%5En%20f_i%7D)
And is useful construct a table like this one:
Speed Freq Midpoint Freq*Midpoint
42-45 21 43.5 913.5
46-49 15 47.5 712.5
50-53 6 51.5 309
54-57 4 55.5 222
58-61 2 59.5 119
Total 48 2276
And the mean is given by:
![\bar X = \frac{2276}{48}=47.417](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20%5Cfrac%7B2276%7D%7B48%7D%3D47.417)
If we compare this value with the 47.3 proposed we have the following error
![Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%](https://tex.z-dn.net/?f=%20Error%20%3D%20%5Cfrac%7B%7CActual-real%7C%7D%7Breal%7D%2A100%20%3D%20%5Cfrac%7B%7C47.417-47.3%7C%7D%7B47.3%7D%2A100%20%3D0.247%5C%25)
The computed mean is close to the actual mean because the difference between the means is less than 5%.
(3x+7)(x-1)=0
3x+7=0
x= -7/3
x-1=0
x=1
She should use 50% off.
964 divided by 1/2 = $482
964 - 400 = $564
Answer:
(x +1) (x + 5)
Step-by-step explanation:
Factorization of x²+6x+5
To factorise this quadratic expression we'll find 2 factors of 5 that when added gives the coefficient of x which is
Factors = +1 and +5
Sum = +6, product = +5
Rewriting equation
x² + x + 5x + 5
Factorising
x ( x +1) +5 ( x + 1)
(x +1) (x + 5)
I hope this was helpful, please mark as brainliest
Answer:
Since we do not know the balance we should start with, a general answer:
![b_{new} = b_{old} + \sum_{i} d_{i} - \sum_{j} w_{j} \\](https://tex.z-dn.net/?f=b_%7Bnew%7D%20%3D%20b_%7Bold%7D%20%2B%20%5Csum_%7Bi%7D%20d_%7Bi%7D%20-%20%5Csum_%7Bj%7D%20w_%7Bj%7D%20%5C%5C)
598 - 47,27 = 550,73, assuming b_old was 0$ for your example
Step-by-step explanation:
b stands for balance (old - before any deposits or withdrawals, new after all done)
d for deposits
w for withdrawals