Answer:
yes, it is a function
D: {-4, -3, 0, 4}
R: {2, 4}
Step-by-step explanation:
Answer:
Step-by-step explanation:
Write a list of all possible outcomes
1-2
1-3
1-4
2-1
2-3
2-4
3-1
3-2
3-4
4-1
4-2
4-3
There are 12 possible outcomes. How many of them have totals of 6 or 7
I count 4
So the probability is 4/12 = 1/3, just as you said.
Is there an easier way?
You might be able to get the 12 easier.
You have 4 choices for the first number and 3 for the second.
P(12) = 4*3 = 12
Getting 6 or 7 might be somewhat trickier.
4 and 3 make seven. That gives two ways 4-3 and 3-4
4 and 2 make six. That gives 2 more ways 4-2 and 2-4
That's all that's possible.
answer: 4 ways make success. The total number of ways is 12.
Answer:
x^2-12x+27
Step-by-step explanation:
(x-3)(x-9)=x^2-3x-9x+27=x^2-12x+27
![\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5Be%5E%7B2y%7D-y%5Ccos%20xy%5Cright%5D%3D2e%5E%7B2y%7D-%5Ccos%20xy%2Bxy%5Csin%20xy)
![\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20x%7D%5Cleft%5B2xe%5E%7B2y%7D-y%5Ccos%20xy%2B2y%5Cright%5D%3D2e%5E%7B2y%7D%2By%5Csin%20xy)
The partial derivatives are not equal, so the equation is not exact.
