All categories

3 years ago

Write the fraction 39 over 9th a repeating decimal

Mathematics

1 answer:

Artist 52 [7]3 years ago

5 0

39 over 9th as a repeating decimal is 4.33 ( the 3 keeps repeating )
I hope this helps!

You might be interested in

Which expression are equivalent to 4+4x+2y+x-y)?

In-s [12.5K]

Answer:

The answer to that is 5x+y+4 but the equivalent is

4(3x + y) and 12x + 4y

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Help!1!1!1 ASAP please !1!1

gulaghasi [49]

Answer:

1/4 Teaspoons: 7

1/3 Cup: 20

Step-by-step explanation:

1/3 Cup:

Butter (2), Sugar (4), Coca (3), Flour(11)

1/4 Teaspoon:

Salt (3), Baking Soda (4)

4 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

ehidna [41]

Answer: 1) 0.10

2) 0.60

3) 0.20

4) 0.10

<u>Step-by-step explanation:</u>

The total frequency is 20+120+40+20 = 200. This means they ran the experiment 200 times. The probability distribution is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):

$\begin{array}{c|c||lc}\underline{x}&\underline{f}&\underline{f\div 200}&\underline{\text{Probability Distribution}}\\1&20&20\div200=&0.10\\2&120&120\div 200=&0.60\\3&40&40\div 200=&0.20\\4&20&20\div 200=&0.10\end{array}\right]$

6 0

3 years ago

In a September 2019 survey of adults in the U.S., participants were asked if within the last 5 years, they knew of a friend or f

kvv77 [185]

Answer:

yes, it is interval.

8 0

3 years ago

How do I solve

Maslowich

$Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}$

4 0

3 years ago