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Artist 52 [7]
2 years ago
8

HELP PLZ I REALLY NEED HELP

Mathematics
1 answer:
tigry1 [53]2 years ago
4 0

Answer:

2.4 miles in total

Step-by-step explanation:

"this answer needs to be atleast 20 characters long"

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81 + 7x² +8yt-sx<br> if x = 2 what is the answer
lilavasa [31]

ANSWER:

109 + 8yt - 2s

WORKING:

81 + 7x² + 8yt - sx

81 + 7(2)² + 8yt - s(2)

81 + 7(4) + 8yt - 2s

81 + 28 + 8yt - 2s

81 + 28 + 8yt - 2s

109 + 8yt - 2s

6 0
2 years ago
What is the first step needed to solve (3/4)x-3=-18 ?
inn [45]
First step is Add 3 to both sides
hope it  helps
3 0
2 years ago
JK has a midpoint at M(7, 2). Point J is at (7, 4). Find the coordinates of point K.
Svetllana [295]

The coordinates of point K(7, 0).

Given, JK has midpoint M(7, 2).

And, the coordinates of point J(7, 4).

We have to find the coordinates of point K.

As M is the midpoint, therefore by using the midpoint formula.

(xₙ + yₙ) = (x₁ + x₂/2 , y₁ + y₂/2)

Using x-coordinates,

xₙ = x₁ + x₂/2

7 = x₁ + 7/2

14 = x₁ + 7

or x₁ = 7

Nos using y-coordinates,

yₙ = y₁ + y₂/2

2 = y₁ + 4/2

4 = y₁ + 4

y₁ = 0

Therefore, the coordinates of point K(7, 0).

The coordinates of J(7, 4); K(7, 0); and M(7, 2).

To learn more about midpoints, visit: brainly.com/question/4637646

#SPJ9

4 0
1 year ago
P=D•W what does this mean in a formula
Snowcat [4.5K]
Pendants =directly•width
6 0
2 years ago
Read 2 more answers
The line defined by the equation 2y+3=-(2/3)(x-3) is tangent to the graph of g(x) at x=-3. What is the value of the limit as x a
Otrada [13]
<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>\boxed{ -\frac{1}{3} }
8 0
2 years ago
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