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3 years ago

HELP PLZ I REALLY NEED HELP

Mathematics

1 answer:

tigry1 [53]3 years ago

4 0

Answer:

2.4 miles in total

Step-by-step explanation:

"this answer needs to be atleast 20 characters long"

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Someone please help...

Viefleur [7K]

Answer:

2 1/3

1 4/3

2.333...

233.3...%

Step-by-step explanation:

3 0

3 years ago

Simplify completely quantity 8 x minus 56 over quantity x squared minus 49 divided by quantity x minus 6 over quantity x squared

34kurt

Hello

So the question ask to simplify the said equation. In getting its answer base on that equation you must first factor out each of them then find out the common of them to cancel them out that could lead you to your answer. In my calculation, the answer is D. 8 open parentheses x plus 4 close parentheses over quantity x minus 6. I hope this would help you

Have a nice day

6 0

3 years ago

Can someone do this for me were doing convert customary lenghts

omeli [17]

I could help if I had a picture of the problem

5 0

3 years ago

Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

3 years ago

Pwease help me anyone. thanks :-) :-) :-) :-) :-) :-) :-) :-)!!!!

adell [148]

A)
$x+3$

b)
$x(x+3)=340\\
x^2+3x-340=0$

c)
$x(x+3)=340\\ x^2+3x-340=0\\
\Delta=3^2-4\cdot1\cdot(-340)=9+1360=1369\\\sqrt{\Delta}=37\\
x_1=\dfrac{-3-37}{2}=-20\\
x_2=\dfrac{-3+37}{2}=17$

It's 17.

3 0

3 years ago