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LUCKY_DIMON [66]
3 years ago
14

If f(x)=2x-5, what is value of f(6)

Mathematics
1 answer:
mars1129 [50]3 years ago
7 0

The value of f(6) = 7

2 x 6 = 12 - 5 = 7

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grandymaker [24]

Answer:

the queation says from ques no 2 so you should take a full picture

3 0
3 years ago
Drag the expressions to show the order of their quotients from least to greatest
Damm [24]

Answer:

by solving the divisions

Step-by-step explanation:

  • 8/9 ÷ 7/11 = 8/9 × 11/7 = 88/63 = 1.40
  • 19/12 ÷ 3/10 = 19/12 × 10/3 =190/36 = 5.28
  • 19/12 ÷ 1/15 = 19/12 × 15 = 285/12 = 23.75

8/9 ÷ 3/10 = 8/9 × 10/3 = 80/27 = 2.96.

now from the solutions you can get the least to greatest

1.40 , 2.96, 5.28 and 23.75

After getting answer in decimal form change it to fraction like how they set the question

8 0
2 years ago
Frank is going to buy some ties
Fudgin [204]

Answer:

  6 shirts

Step-by-step explanation:

The cost of a shirt and 2 ties is ...

  $18.50 +2(7.50) = $33.50

For $205, Frank can buy $205/$33.50 = 6.12 sets of shirt and ties.

Frank can buy 6 shirts (and 12 ties) for an amount less than $205.

_____

<em>Additional comment</em>

Frank's cost will be $201 for that purchase.

3 0
2 years ago
(5x^3-8x^2+9x+12)/(x-3)<br><br> please answer with sentences on how to do it step by step. thanks!
Anastaziya [24]

Answer:

5x^2+7x+30+\frac{102}{x-3}

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}

6 0
3 years ago
Read 2 more answers
The table shows list of walking trails in the United States. Latisha walked the KATY trail six days last week. How many miles di
myrzilka [38]
How long is the trail on your table then multiply by 6.
7 0
3 years ago
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