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gladu [14]
3 years ago
7

Write each ratio in the simplest form (Note, semember the units of

Mathematics
2 answers:
quester [9]3 years ago
8 0

Answer:

Write each ratio in the simplest form (Note, semember the units of

measurement, they must be the same!)

30 in to 1 ft PLZ HELP ME!!!!

Step-by-step explanation:

im here for the points

im here for the points

im here for the points

Gre4nikov [31]3 years ago
6 0

Step-by-step explanation:

e8dnfhdjudufifnf8if9xbdu

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What is the value of x? <br><br> A. 68° <br> B. 62° <br> C. 112° <br> D. 124
bearhunter [10]
The triangle drawn in the question shows a small single line drawn across two sides of the triangle.

This means that those two sides are equal in length.

Hence, the triangle is an isosceles triangle.

In isosceles triangles, the angles opposite to the equal sides are also equal.

Hence, we know that the two angles other than x is 56°.

The sum of the interior angles of a triangle is 180°

x + 56 + 56 = 180

x = 180 - 56 - 56

x = 180 - 112

x = 68°

Hence, the answer is A.
5 0
3 years ago
Read 2 more answers
F(x)= 7.45x +33.7 at x=-4.3
weeeeeb [17]

To solve this function, all we need to do is substitute -4.3 in for wherever "x" appears and then simplify.

f(x) = 7.45x + 33.7; x = -4.3

f(-4.3) = 7.45(-4.3) + 33.7

f(-4.3) = -32.035 + 33.7

f(-4.3) = 1.665

This means that, when x = -4.3, f(x) = 1.665.

Note: It may help to remember that, in a function such as this, f(x) can be thought of as the "y" value that corresponds to the given "x" value (in fact, when writing it out with words, f(x) is the same as "function of x"). And, if you are given a value for f(x), then the opposite is true. Just substitute in the value given for f(x) and solve for x.

Hope this helps!

8 0
3 years ago
Binomial Expansion/Pascal's triangle. Please help with all of number 5.
Mandarinka [93]
\begin{matrix}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\end{bmatrix}

The rows add up to 1,2,4,8,16, respectively. (Notice they're all powers of 2)

The sum of the numbers in row n is 2^{n-1}.

The last problem can be solved with the binomial theorem, but I'll assume you don't take that for granted. You can prove this claim by induction. When n=1,

(1+x)^1=1+x=\dbinom10+\dbinom11x

so the base case holds. Assume the claim holds for n=k, so that

(1+x)^k=\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k

Use this to show that it holds for n=k+1.

(1+x)^{k+1}=(1+x)(1+x)^k
(1+x)^{k+1}=(1+x)\left(\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k\right)
(1+x)^{k+1}=1+\left(\dbinom k0+\dbinom k1\right)x+\left(\dbinom k1+\dbinom k2\right)x^2+\cdots+\left(\dbinom k{k-2}+\dbinom k{k-1}\right)x^{k-1}+\left(\dbinom k{k-1}+\dbinom kk\right)x^k+x^{k+1}

Notice that

\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!}{\ell!(k-\ell)!}+\dfrac{k!}{(\ell+1)!(k-\ell-1)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)}{(\ell+1)!(k-\ell)!}+\dfrac{k!(k-\ell)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)+k!(k-\ell)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(k+1)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{(k+1)!}{(\ell+1)!((k+1)-(\ell+1))!}
\dbinom k\ell+\dbinom k{\ell+1}=\dbinom{k+1}{\ell+1}

So you can write the expansion for n=k+1 as

(1+x)^{k+1}=1+\dbinom{k+1}1x+\dbinom{k+1}2x^2+\cdots+\dbinom{k+1}{k-1}x^{k-1}+\dbinom{k+1}kx^k+x^{k+1}

and since \dbinom{k+1}0=\dbinom{k+1}{k+1}=1, you have

(1+x)^{k+1}=\dbinom{k+1}0+\dbinom{k+1}1x+\cdots+\dbinom{k+1}kx^k+\dbinom{k+1}{k+1}x^{k+1}

and so the claim holds for n=k+1, thus proving the claim overall that

(1+x)^n=\dbinom n0+\dbinom n1x+\cdots+\dbinom n{n-1}x^{n-1}+\dbinom nnx^n

Setting x=1 gives

(1+1)^n=\dbinom n0+\dbinom n1+\cdots+\dbinom n{n-1}+\dbinom nn=2^n

which agrees with the result obtained for part (c).
4 0
3 years ago
Is it possible for you guys to read a book called the giver and then write a whole essay, can you please do it it’s due tomorrow
STatiana [176]

Answer:

No

Step-by-step explanation:

We are not just going to do your writing essay for you. It's your fault you didn't get it done.

4 0
3 years ago
100 POINTS IF U GET THIS RIGHT!
ANTONII [103]

\begin{gathered}\\ \sf\longmapsto Area\:of\:rectangle=Length×Breadth\end{gathered}

<h3>Here,</h3>
  • Length= 13.8 ft
  • Breadth= 11.9 ft

\begin{gathered}\\ \sf\longmapsto Area=13.8×11.9\end{gathered}

\begin{gathered}\\ \sf\longmapsto ⚘Area=164.22ft^{2}\end{gathered}

3 0
2 years ago
Read 2 more answers
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