This is essentially asking how many different ways to partition 6 into 3 segments.
I am assuming "no ball in a box" is not allowed.
6 can be partitioned as
(4,1,1), (3,2,1), and (2,2,2)
So, calculate each partition, we get
(6 choose 4) + (6 choose 3)*(3 choose 2) + (6 choose 2) * (4 choose 2)
= 15 + 20*3 + 15*6
=165
Answer:
Step-by-step explanation:
We need to use the properties shown below to solve this:
1. ![\sqrt[n]{x^a} =x^{\frac{a}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ea%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bn%7D%7D)
2. 
3. 
Area of a triangle is given by 1/2 * base * height, so we do that and simplify:
EHRP, EHFG, EFPQ Does that make sense?
Answer: 26.4
To find the volume u multiply 12x2.2=26.4
