In quadrilateral ABCD, diagonals AC and BD bisect one another:

1 answer:

3 0

1) 1)Angles BAD and ADC are congruent - false the angles on the same side, the are supplementary , not congruent
2) Corresponding angles BCD and CDA are supplementary. True, but it does not prove that that quadrilateral ABCD is a parallelogram
3)Sides CD and DA are congruent. false , they are connected to the same vertex
4)Triangles BPA and DPC are congruent. - the answer

You might be interested in

Find the value of x so that the function has the given value. n(x) = -6x + 2; n(x) = 44

nalin [4]

9514 1404 393

Answer:

x = -7

Step-by-step explanation:

Substitute the given value and solve for x

n(x) = -6x +2

44 = -6x + 2

42 = -6x . . . . . subtract 2

-7 = x . . . . . . . divide by -7

n(x) will have the value 44 for x = -7.

6 0

3 years ago

10. Given matrices A, B, and C below, perform the indicated operations if possible. If the operation is not possible, explain wh

Artemon [7]

Answer(a):

Order of matrix A = 3x3 {because number of rows=3, number of columns=3}

Order of matrix B = 3x3

Order of matrix C = 1x3

3A will be of order 3x3 because multiply by scalar doesn't change the order. Which is same as the order of matrix B.

So 3A+B is possible.

We simply multiply all elements of A with 3 and add them with corresponding elements of B.

$3\begin{bmatrix}2 & -1& 0\\ 0 & 5& 0.3\\ 1 & 4&10 \end{bmatrix}+\begin{bmatrix}5 & 0& 2\\ 1 & -3& 9\\ 2 & 0& 4\end{bmatrix}= \begin{bmatrix}11 & -3& 2\\ 1 & 12& 9.9\\ 5 & 12& 34\end{bmatrix}$

Answer(b):

2B will be of order 3x3 because multiply by scalar doesn't change the order. Which is NOT same as the order of matrix C.

So 2B+C is NOT possible.

Answer(c):

CA is possible only if

number of columns of C = number of columns of A

3=3

which is true hence CA is possible.

$\begin{bmatrix}1 &3 &5 \end{bmatrix}*\begin{bmatrix}2 & -1& 0\\ 0 & 5& 0.3\\ 1 & 4&10 \end{bmatrix}=\begin{bmatrix}1*2+3*0+5*1 & 1*-1+3*5+5*4 & 1*0+3*0.3+5*10\end{bmatrix}$