Answer:

Step-by-step explanation:
There are infinite answers
All you have to do is changed the last number 3, to any real number greater or less than 3
Answer:
-5
Step-by-step explanation:
Substituting x=4 into the equation gives a 2-step linear equation in y. It is solved by isolating the variable and making its coefficient be 1.
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<h3>use x=4</h3>
When x=4, the equation becomes ...
-3x +9y = -57
-3(4) +9y = -57
-12 +9y = -57
<h3>solve 2-step equation</h3>
The <u>first step</u> is to "isolate" the variable term (9y) by adding the opposite of the constant that is on the same side of the equation. The result is that the variable term is by itself on one side of the equal sign.
-12 +12 +9y = -57 +12 . . . . . add the opposite of -12
9y = -45 . . . . . . . . . . . . . . simplify
The <u>second step</u> is to make the coefficient of y be 1. We do that by multiplying by its inverse, 1/9. Equivalently, we divide by 9.
(1/9)(9y) = (1/9)(-45) . . . . multiply by the inverse of 9
y = -5 . . . . . . simplify
My guess would be guess A
7x+5y=-24 (1)
4x+y=42 (2)
multiply equation (2) by 5 to get
20x+5y=210 (3)
then calculate (3)-(2) which gives you
13x=234 hence x=18
then substitute for x in either equation to get y=-30
Answer:
2nd car is running faster than the first car by 2.01 units.
Step-by-step explanation:
Let's assume that
- the velocity of first car,

- and the velocity of second car

=> speed of first car,



= 32.01 units
and speed of second car,

= 30 units

= 2.01 units
Hence, 2nd car is running faster than the first car by 2.01 units.