Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.
X=23 First, you have to subtract 12 by 12 to cancel it out. Next, you have to do the same thing to 20.05. 20.05 minus 12 is 8.05. All you have left is .35x. To get rid of the this you have to divide .35x by .35. Now all you have left is x. Finally you have to do the same thing to 8.05. 8.05 divided by .35 is 23. So, x=23
Answer:
56 degrees.
Step-by-step explanation:
We need the measure of < g.
The triangle formed by the 2 tangents and the chord is isosceles, because 2 tangents from a point outside a circle are of equal length (by the Two Tangents theorem).
Also one of the base angles are equal to 62 degrees ( by The Tangent Chord theorem). In fact both base angles are 62 degrees because the triangles an isosceles.
So measure of angle g = 180 - 2(62)
= 56 degrees.
