Answer:
3/4 is like 75%cause it's most but not all and there are 4quarters in a dollar witch r 25 cents each so 3 out of 4 quarters is 75cents so it's 75%
I'm assuming

(a) <em>f(x)</em> is a valid probability density function if its integral over the support is 1:

Compute the integral:

So we have
<em>k</em> / 6 = 1 → <em>k</em> = 6
(b) By definition of conditional probability,
P(<em>Y</em> ≤ 0.4 | <em>Y</em> ≤ 0.8) = P(<em>Y</em> ≤ 0.4 and <em>Y</em> ≤ 0.8) / P(<em>Y</em> ≤ 0.8)
P(<em>Y</em> ≤ 0.4 | <em>Y</em> ≤ 0.8) = P(<em>Y</em> ≤ 0.4) / P(<em>Y</em> ≤ 0.8)
It makes sense to derive the cumulative distribution function (CDF) for the rest of the problem, since <em>F(y)</em> = P(<em>Y</em> ≤ <em>y</em>).
We have

Then
P(<em>Y</em> ≤ 0.4) = <em>F</em> (0.4) = 0.352
P(<em>Y</em> ≤ 0.8) = <em>F</em> (0.8) = 0.896
and so
P(<em>Y</em> ≤ 0.4 | <em>Y</em> ≤ 0.8) = 0.352 / 0.896 ≈ 0.393
(c) The 0.95 quantile is the value <em>φ</em> such that
P(<em>Y</em> ≤ <em>φ</em>) = 0.95
In terms of the integral definition of the CDF, we have solve for <em>φ</em> such that

We have

which reduces to the cubic
3<em>φ</em>² - 2<em>φ</em>³ = 0.95
Use a calculator to solve this and find that <em>φ</em> ≈ 0.865.
Answer:
124 students
Step-by-step explanation:
let number of boys be 11x and girls be 9x.
A.T.Q 124 more boys than girls
equation=
11x = 9x + 124
11x- 9x = 124
2x = 124
x = 124/2 = 62
boys= 62 * 11 = 682
girls= 62 * 9 = 558
total = 558+682 = 1240 students
Answer:
vertex is: (4,-9)
y intercept= (0,7)
roots= (1,0) and (7,0)
Step-by-step explanation:
so we can use factoring to solve this quadratic equation real quick:
x^2-7x-1x+7
x(x-7)
-1(x-7)
(x-1)(x-7)=0
x-1=0
x=1
x-7=0
x=7
(1,0) and (7,0) are the roots
axis of symmetry: 8/2=4
substitute axsis of symmetry in equation to get vertex:
4^2-8(4)+7
16-32+7
-16+7=-9
vertex is: (4,-9)
y intercept= (0,7)
roots= (1,0) and (7,0)
Hope this helps