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Alchen [17]
3 years ago
6

What is up guys!

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Answer:

  • Yes, No, Yes

Step-by-step explanation:

<u>Use the Pythagorean theorem:</u>

  • a² + b² = c²

<u>Verify this for each line:</u>

1.

  • 28² + 45² = 53²
  • 2809 = 2809
  • Yes

2.

  • 33² + 56² = 64²
  • 4225 ≠ 4096
  • No

3.

  • 36² + 77² = 85²
  • 7225 = 7225
  • Yes
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k0ka [10]
\frac{1}{3} (n + 15) = -2

First, replace the numerator with the parentheses.
\frac{n+15}{3} =-2
Second, multiply both sides by 3.
n + 15 = -2 * 3
Third, multiply 2 × 3 to get 6.
n + 15 = -6
Fourth, take away 15 from each side.
n = -6 - 15
Fifth, simplify -6 - 15 to get -21.
n = -21

Answer: n = -21

3 0
3 years ago
John read the first 114 pages of the novel, which was 3 less than 1/3 of the novel
Nastasia [14]
Let p = total pages in the book 
<span>114 pages of a novel which was 3 pages less than 1/3 </span>
<span>114 was 1/3 total pages - 3 pages </span>
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6 0
3 years ago
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A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient
ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

y=(x-a) \sqrt{(x-b)}  --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

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According to multiple rule of Differentiation,

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By putting value of point A and putting value of eq 2 we get

y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}

y^{\prime}=\frac{d y}{d x}=1

Hence proved that the gradient of the curve at A is 1.

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3 years ago
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Yuki888 [10]

Yes -1 is a rational number. We can express it as a fraction of two whole numbers

One way is -1 = -1/1

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