Find the area of the shaded regions plzz asap ill give brainliest

what do i do if i have meausring cups but it doesnt say how much they are? i really wanna make some cookies

olya-2409 [2.1K]

Try measuring a different way, maybe with just cups

5 0

3 years ago

Jack is at the zoo looking up at a monkey

sasho [114]

The height of the pole at which the monkey is at the top is 10.2 feet.

<h3>Trigonometric ratio</h3>

Trigonometric ratio is used to show the relationship between the angles and sides of a right angled triangle.

Let h represent the height of the pole, hence using trigonometric ratio:

tan(23) = h/24

h = 10.2 feet

The height of the pole at which the monkey is at the top is 10.2 feet.

Find out more on Trigonometric ratio at: brainly.com/question/4326804

4 0

1 year ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

The width of a rectangle is x. Its length is 3x. How long is the diagonal of the rectangle? Express your answer in simplified ra

nikklg [1K]

Answer:

The length of the diagonal is x√10

Step-by-step explanation:

Here, we want to find the length of the diagonal

The diagonal will represent the hypotenuse of a triangle formed with the width and length of the triangle being the measure of the other sides

Mathematically, we then apply Pythagoras’ theorem to get this

we have this as that the square of the diagonal equals the sum of the squares of the two other sides

d^2 = x^2 + (3x)^2

d^2 = x^2 + 9x^2

d^2 = 10x^2

d = √(10x^2)

d = x√10

7 0

2 years ago

7 apples cost 4.55 dollars how much do 9 apples cost

Lubov Fominskaja [6]

To calculate how much 9 apples cost, you must multiply 9 to 4.55 and then divide by 7. This is done by setting up a proportion.

7 0

3 years ago

Find the area of the shaded regions plzz asap ill give brainliest ​

Find the area of the shaded regions plzz asap ill give brainliest