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Natalka [10]
3 years ago
7

There were 632 animals gathered at the river. A herd of 187 elephants and 266 zebras left the river area. How many animals were

still at the river?
Mathematics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

179 animals were still at the river

Step-by-step explanation:

There were 632 animals at the river.

A herd of 187 elephants and 266 zebras left the river area.

This means that 187 + 266 = 453 animals left the river area.

Remaining:

632 - 453 = 179

179 animals were still at the river

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The answer would be '2'.
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3 years ago
Please help and explain
antoniya [11.8K]

Charlie makes 8 kilograms of dough every hour. If he works for 4 hours preparing the dough, then Charlie would have prepared 32 kilograms of dough.

So you have 8 kilograms every hour.

8:1

There are 4 hours that Charlie works on preparing dough. That would be 1 times 4. What you do to one side, you must do to the other.

8 times 4 is 32.

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Charlie makes 32 kilograms.

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Will earned $90 interest on his investment account. He originally deposited $500 and got %6 simple interest. For how many years
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8 0
3 years ago
The concept of determining which reactant is limiting and which is in excess is akin to determining the number of sandwiches tha
Alona [7]

Answer: There are 22 whole cheese sandwiches that can be prepared.

Step-by-step explanation:

Since we have given that

Number of slices of bread = 44

Number of slices of cheese = 75

According to question, a cheese sandwich consists of 2 slices of bread and 3 slices of cheese.

So, we need to find the number of whole cheese sandwiches that can be prepared.

Number of sandwich containing only slice of bread is given by

\dfrac{44}{2}=22

Number of sandwich containing only slice of cheese is given by

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As we know that each sandwich should contain both slice of bread and slice of cheese.

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3 0
4 years ago
What’s the length of the segments variable expressions ??
maxonik [38]

Answer:

EF=9\ units

Step-by-step explanation:

we know that

The <u><em>Trapezoid Mid-segment Theorem</em></u> states that: A line connecting the midpoints of the two legs of a trapezoid is parallel to the bases, and its length is equal to half the sum of lengths of the bases

so In this problem

EF=\frac{1}{2}[AD+BC]

substitute the given values

x=\frac{1}{2}[(x-6)+(2x-3)]

x=\frac{1}{2}[3x-9]

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so

AD=x-6=9-6=3\ units

EF=x=9\ units

BC=2x-3=2(9)-3=15\ units

4 0
3 years ago
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