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garri49 [273]
2 years ago
9

When using the formula P + 1 you are looking for

Mathematics
1 answer:
Montano1993 [528]2 years ago
8 0

Answer:

I think its D I am sorry if I am wrong

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Which describes the correct way to convert minutes to hours? Divide the number of minutes by 24 Multiply the number of minutes b
fenix001 [56]

Answer:

divide the number of minutes to hours

8 0
3 years ago
The Anderson's are driving 2,563 miles to the beach. They plan to drive 325 miles a day. How many days will it take the Anderson
12345 [234]

Answer:

Around 8 days

Step-by-step explanation:

Divide 325 from 2,563

2563 / 325 = 7.888

Round that number

3 0
3 years ago
Hi, can someone please answer this questions, THANKS
aliya0001 [1]

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supplementary angles add up to 180 degrees and complementary add up to 90 degrees

Step-by-step explanation:

3 0
3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
Is 6,8,9 a pythagorem theorem? pls help me due rn
Naddika [18.5K]

Answer:

No, it isn't.

Step-by-step explanation:

Pythagorean theorem is x^2 + y^2 = z^2.

6^2 + 8^2 = 9^2

36 + 64 = 81

100 = 81

So, it isn't.

4 0
2 years ago
Read 2 more answers
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