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densk [106]
3 years ago
11

How can I solve 25x - 10y?​

Mathematics
1 answer:
IRISSAK [1]3 years ago
6 0
5(5x-2y)



not sure.....
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Use Desmos the graphing app it's great!
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3 years ago
Find the 14th term of the geometric sequence 5 -10 20
Anna [14]

Answer:

  a14 = -40,960

Step-by-step explanation:

The sequence has a first term of 5 and a common ratio of -10/5 = -2, so the n-th term is given by ...

  an = a1·r^(n-1)

  an = 5·(-2)^(n-1)

The 14th term is then ...

  a14 = 5·(-2)^(14-1) = -5·2^13 = -5·8192

  a14 = -40,960

7 0
3 years ago
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Can someone help me understand the concept of finding the domain and range on a graph. I don’t understand it! Someone help me
juin [17]

Answer:

The Domain is where the line on your graph crosses the X axis.

The Range us where the line on your graph crosses the Y axis

And a arrow means it goes Into infinity

Step-by-step explanation:

Say you Have a line, it crosses the X axis at -3, your Domain would be -3!

Now say this line crosses the Y axis at -6, Your Range would be -6!

And now say if instead of the line ending at a dot after crossing -6 It has a arrow, that means you have infinity, Making your range instead of -6 it's be infinity! (If the arrow points up it's positive infinity, If the arrow points down it's negative infinity)

So for the first 2 numbers your answer would be [-3,-6] and in you have infinity itd be [-3, infinity) parenthesis isn't a error btw if you still don't get it I can just reply with a sheet I have on it

5 0
3 years ago
Help me ASAP plssssssssssssssss
marishachu [46]

Answer: it’s B

Step-by-step explanation:

8 0
3 years ago
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A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan
seropon [69]

Answer:

32 unit^{3}

Step-by-step explanation:

Given:

  • The slant length 10 units
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Now we use  Pythagoras to get the slant height in the middle of each triangle:

\sqrt{10^{2 - (4\sqrt{2} ^{2} }) } = \sqrt{100 - 32} = \sqrt{68}  units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

\sqrt{68-(4\sqrt{2} ^{2} )} = \sqrt{68 - 32} = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:

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So the volume of it is:

V  = 1/3 *3* 4\sqrt{2}

= 32 unit^{3}

5 0
3 years ago
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