Answer: (110.22, 125.78)
Step-by-step explanation:
The confidence interval for the population mean is given by :-

Given : Sample size = 463


Significance level : 
Critical value : 
We assume that the population is normally distributed.
Now, the 90% confidence interval for the population mean will be :-

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)
OK so here it goes:
1a. 10³
1b. 10²
1c. 10(tiny 6)
1d. 10³
1e. 10(tiny6)
1f. 10(tiny 5)
2a. 400
2b. 640,000
2c. 5,400
2d. 5,301,000
2e. is it multipcation or addition
2f. 607,200
2g. 0.948
2h. 0.0094
3a) 0.02, 0.2, 2, 20, 200, 2000
3b) 3,400,000 ; 34,000; 340, 3.4, 0.034
3c) 85,700; 8,570; 857, 85.7, 8.57, 0.857
3d) 444, 4440, 44,400; 440,000; 4,400,000; 44,000,000
3e) 0.95, 9.5, 950, 95,000; 950,000; 9,500,000
Hope this helps.
The mean is the average.
Add all the number of pets and divide by how many people there were.
3+5+2+4+1
15/number of people
15/5
=3
Hope this helps :)
12/36 = x/100
Then cross multiply
1200 = 36x
Divide by 36
x = 33.33
Can’t sell 0.33 of an appliance, so your answer is 33.
Answer:
Part a) The constant of proportionality of Kevin's wage is 
Part b) The constant of proportionality of Greg's wage is 
Part c) The constant of proportionality of Savannah's wage is 
Step-by-step explanation:
See the attached figure to better understand the problem
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
or
To find out the constant of proportionality k , divide the variable y (total earned) by the variable x (number of hours)
<em>Kevin's wage</em>
Take any point from the table
I take the point (2,16.50)

<em>Greg's wage</em>
Take any point from the table
I take the point (3,27.00)

<em>Savannah's wage</em>
Take any point from the table
I take the point (2,19.00)
