Question

A school baseball team has 65 players. What is the probability that a randomly chosen player is a junior or a right handed batter?

Answer 1

Answer:

$Probability = \frac{51}{65}$

Step-by-step explanation:

Given (Missing from the question)

$\begin{array}{ccccc}{} & {Freshman} & {Sophomore} & {Junior} & {Senior} &{Left-handed batters} & {4} & {6} & {5} & {4} & {Right-handed batters} & {13} & {10} & {11} & {12}\ \end{array}$

$Total = 65$

Required

Determine the probability of selecting a junior or right handed batter

From the table above:

$R=13 + 10 + 11 + 12 =46$ ---- Right handed

$J = 5 + 11 = 16$ --- Junior

$R\ and\ J = 11$ ---- Right handed and Junior

The probability of right handed player of junior player being selected is:

$Probability = P(R) + P(J) - P(R\ and\ J)$

$Probability = \frac{n(R) + n(J) - n(R\ and\ J)}{Total}$

$Probability = \frac{46+16-11}{65}$

$Probability = \frac{51}{65}$