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4 years ago

A scale on a map shows that 2 inches = 25 miles.

Mathematics

2 answers:

zepelin [54]4 years ago

5 0

Part a- 4.8 inches
part b- 3.125 inches

Mumz [18]4 years ago

4 0

Part A : it would be 4.8 inches
Part B : 1/4 inch would equal 3.125

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Solve 2/3x> 8 or 2/3x< 4

grigory [225]

Answer:

x > 12

Answer for 2/3>8

8 0

3 years ago

Read 2 more answers

This too!! Once again, thank you!

Volgvan

Answer:

For question 3, the slope would be -5

Step-by-step explanation:

If you wanted to graph this you would have to plot one of the points that is already given. Then from that point, you would move 5 units down and 1 unit to the right. If you run out of space, you can go to the other direction by going 5 units up and 1 to the left.

Hope this helps :)

8 0

2 years ago

If a line has a slope of 3, what is the slope of a perpendicular line?

pashok25 [27]

Answer:

Slope of perpendicular line is -1/3

Step-by-step explanation:

The slope of the given line is 3 and we have to find the slope of the perpendicular line.

We know that the slope of two perpendicular lines are negative reciprocal of each other.

In other words if the slope of the line is m then then slope of the perpendicular line is $-\frac{1}{m}$

The reciprocal of 3 is $\frac{1}{3}$

Hence, negative reciprocal of 3 is $-\frac{1}{3}$

Therefore, the slope of perpendicular line is -1/3

C is the correct option.

6 0

3 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .