What is the point-slope form of a line that has a slope of 5 and passes through the point (3, –4)?

2 answers:

Alex2 years ago

8 0

The answer is: y - (-4)= 5(x-3)

Point slope form is:
y-y1=m(x-x1)

m is your slope. They tell us the slope is 5. They also give you an ordered pair. Substitute this ordered pair into the point slope equation for the x1 and y1 values.

zloy xaker [14]2 years ago

3 0

Answer:

The answer is: y - (-4)= 5(x-3)

Point slope form is:

y-y1=m(x-x1)

m is your slope. They tell us the slope is 5. They also give you an ordered pair. Substitute this ordered pair into the point slope equation for the x1 and y1 values.

brainlest plz

Step-by-step explanation:

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The following system has a solution: x=10, y=-3, z=14

wolverine [178]

<h2>Answer:</h2><h3>False</h3>

<h2>Step-by-step explanation:</h2>

In this problem, we have the following System of Three Equations in Three Variables, so our goal is to determine whether $x=10, \ y=-3, \ z=14$ is the solution to this system, that is, the ordered triple $P(x,y,z)$ where three planes intersect.

The easier way to find the answer is to plug in the x, y and z values in the equations and figure out whether the equations satisfy the solutions. Then:

$First \ Equation: \\ \\ 3(10)+7(-3)-14=-5 \\ \\ It \ satisfies \ the \ first \ equation \\ \\ \\ Second \ Equation: \\ \\ 9(10)-(-3)-4(14)=37 \neq 17 \\ \\ It \ doesn't \ satisfy \ the \ second \ equation$