Assuming that the blank space is a plus
2x^2+12x-14=0
isolate x
(2x^2+12x)-14=0
undistribute 2
2(x^2+6x)-14=0
take 1/2 of 6 and square and add negative and positive
2(x^2+6x+9-9)-14=0
factor perfect squrae
2((x+3)^2-9)-14=0
distribute
2(x+3)^2-18-14=0
2(x+3)^2-32=0
2(x+3)^2=32
divide 2
(x+3)^2=16
sqrt
x+3=+/-4
minus 3
x=+/-4-3
x=-7 or 1
2nd to last option
The correct answers for the exercise shown above, are:
- <span>The numerator has 3 terms:
the first term is:-10x^2
the second term is: 5x
the third term is: 3
- </span>The denominator includes a coefficient of 4:
<span>
2x^2+4
- </span><span>The denominator includes a coefficient of 2:
</span> 2x^2+4
<span>
- The numerator includes a coefficient of 3:
-10x^2+5x+3</span>
Answer: "C"
roots would make the function "0"
so just plug in the numbers...
with a + 12 you need minuses to cancel out...
B & C can not be the answer...
A is -i -3 + 4i - 12 which also is not 0
C is : 8i -12 -8i +12 WHICH DOES = 0
Step-by-step explanation:
(x-10)(x+9) =0
×=10 x=-9
10 + (-9)
= 1
