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mojhsa [17]
3 years ago
6

Select true statements. (-10x^(2)+5x+3)/(2x^(2)+4)

Mathematics
2 answers:
katrin2010 [14]3 years ago
3 0
The correct answers for the exercise shown above, are:

 - <span>The numerator has 3 terms:

 the first term is:-10x^2
 the second term is: 5x
 the third term is: 3

 - </span>The denominator includes a coefficient of 4:
<span>
 2x^2+4

 - </span><span>The denominator includes a coefficient of 2:

 </span> 2x^2+4
<span>
 - The numerator includes a coefficient of 3:

 -10x^2+5x+3</span>
blagie [28]3 years ago
3 0

Answer: True statements::    <u>The numerator has 3 terms; The denominator includes a coefficient of 2.</u>


Step-by-step explanation:


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vova2212 [387]

Area of the Base = 6 * side^2 / 4 * tan (180/6)

Area of the Base = 6 * 16 / 4 * 0.57735

Area of the Base = 96 / 2.3094

Area of the Base = 41.5692387633


Area of 1 Face = 2 * 6 = 12

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3 years ago
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What is the value of -12- (-35)?
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3 years ago
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A line has a slope of –5 and a y-intercept of (0, 3). What is the equation of the line that is perpendicular to the first line a
neonofarm [45]
Slope-intercept form:
y=mx+b
m=slope
b=y-intercept

Data of the first line:
m=-5
b=y-intercept=3  (y-intercept=it is the value of "y" when x=0)

y=-5x+3

A line perpendicular to the line y=mx+b will have the following slope:
m`=-1/m

Therefore: the line perpendicular to the line y=-5x+3 will have the following slope:
m´=-1/(-5)=1/5

Point-slope form of a line: we need a point (x₀,y₀) and the slope (m):
y-y₀=m(x-x₀)

We know, the slope (m=1/5) and we have a point (3,2) therefore:
y-y₀=m(x-x₀)
y-2=1/5(x-3)     (point-slope form)
y-2=(1/5)x-3/5
y=(1/5)x-3/5+2
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Answer: the line perpendicular to the first line will be: y=(1/5)x+7/5



3 0
3 years ago
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