Without knowing anything else about
, neither of these need be true.
Suppose

Then (I) isn't true because, while the limit exists as
and is equal to 7, we have
, so
is not continuous there.
(II) also true because
is not differentiable at
; that is,

but

which means the derivative does not exist at
.
Answer:
I don't have enough info to understand the question?
Step-by-step explanation: