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mojhsa [17]
3 years ago
6

Select true statements. (-10x^(2)+5x+3)/(2x^(2)+4)

Mathematics
2 answers:
katrin2010 [14]3 years ago
3 0
The correct answers for the exercise shown above, are:

 - <span>The numerator has 3 terms:

 the first term is:-10x^2
 the second term is: 5x
 the third term is: 3

 - </span>The denominator includes a coefficient of 4:
<span>
 2x^2+4

 - </span><span>The denominator includes a coefficient of 2:

 </span> 2x^2+4
<span>
 - The numerator includes a coefficient of 3:

 -10x^2+5x+3</span>
blagie [28]3 years ago
3 0

Answer: True statements::    <u>The numerator has 3 terms; The denominator includes a coefficient of 2.</u>


Step-by-step explanation:


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A car has a gasoline
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Yes, look at the explanation:

Step-by-step explanation:

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3 years ago
Verify the identity.<br><br> <img src="https://tex.z-dn.net/?f=cot%20%28x-%5Cfrac%7B%5Cpi%20%7D%7B2%7D%29%3D-tan" id="TexFormula
aleksley [76]

Answer:

True

Step-by-step explanation:

assuming that you meant to write

cot (x-π//2) = - tan x

the identity is TRUE because,

- you can graph cot (x-π//2)  and  - tan x, and see that the graphs overlap

OR

-you solve for cot (x-π/2)

useful to know is that :

cot x=1/tan x, tan x = sin x/cos x,  

cos(x) =cos(-x), sin(-x) = -sin x,

cos(π/2 -x) =sin x, sin (π/2-x) =cos x

cot (x-π/2) = 1/tan (x-π/2) , yet tangent is sin x/cos x

cot (x-π/2) = cos (x-π/2) /sin (x-π/2) , factor -1

cot (x-π/2) = cos -(π/2-x) /sin -(π/2-x),  use facts: cos(x) =cos(-x), sin(-x) = -sin x

cot (x-π/2) = cos (π/2-x) / -sin (π/2-x), use cos(π/2 -x) =sin x, sin (π/2-x) =cos x

cot (x-π/2) = sin x / -cos x , again sin x /cos x = tan x

cot (x-π/2) = -tan x

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Answer: 0.15 meters taller

Step-by-step explanation:

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3 years ago
Let f(x) = x2 + x + 2 and g(x) = 2x2 + 5. Find f(g(x)). Show each step of your work.
OlgaM077 [116]
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4 0
4 years ago
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