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3 years ago

If f(x)=(x-1)^1/3 then what is f^-1(x)

Mathematics

1 answer:

Stels [109]3 years ago

5 0

Answer:

The answer is f−1(x)=1x13

Step-by-step explanation: hi

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(cos A + cos b)^2 + (sin A + sin B)^2=?

emmasim [6.3K]

First, we expand the equation:

$cos^{2}A+2cosAcosB+ cos^{2}B+sin^{2}A+2sinAsinB+sin^{2}B$

Then, we combine certain terms in order to simplify them using trigonometry identities.

$cos^{2}A+sin^{2}A+cos^{2}B+sin^{2}B+2cosAcosB+2sinAsinB$

Note these identities:
Pythagoran relation: $cos^{2}A+sin^{2}A = cos^{2}B+sin^{2}B=1$
Sum and Difference Formula/Identities: $cos(A-B) = cosAcosB+sinAsinB$

Thus, if we apply these identities, the simplified equation would be:
$2(cos(A-B))+2$

Simplying further, the answer would be

$2[cos(A-B)+1]$

6 0

3 years ago

5= h/1.25 help me plz

yKpoI14uk [10]

Answer:

Step-by-step explanation:

5=h/1.25

h=6.25

6 0

3 years ago

On the moon, the height of a golf ball hit with an initial velocity of 96 ft/sec is given by the equation h= -2.7t^2+96t, where

nikdorinn [45]

So hmmm notice the picture below

"x" being how many seconds the object was going

and when y = 0, the object hits the ground, either on the moon or on earth

so, if we set y = 0 on each equation, we'll know when that happen, how long of a "x-value" or seconds it took

$\bf \begin{array}{llll}
\textit{on the moon}\\\\
h=-2.7t^2+96t\implies 0=t(96-2.7t)
\end{array} \quad 
\begin{cases}
0=t\\
-------\\
0=96-2.7t\\
2.7t=96\\
t=\frac{96}{2.7}\\
t\approx 35.\overline{55}
\end{cases}\\\\
-------------------------------\\\\
\begin{array}{llll}
\textit{on earth}\\\\
h=-16t^2+96t\implies 0=t(96-16t)
\end{array} \quad 
\begin{cases}
0=t\\
------\\
0=96-16t\\
16t=96\\
t=\frac{96}{16}\\
t=6
\end{cases}$

4 0

3 years ago

Given Ray BA bisects ∠CBD and the diagram below, what is m∠ABD?

Illusion [34]

The measure of the angle ∠ABD is 64 degrees

<h3>How to determine the measure of the angle?</h3>

From the question, we have the following parameters:

Ray BA bisects ∠CBD

∠CBD = 5x + 18

∠ABC = 3x - 2

Because of the bisection, we have

∠ABC = ∠ABD

∠ABC * 2 = ∠CBD

Substitute the known values in the above equation, so, we have the following representation

(3x - 2) * 2 = 5x + 18

Open the brackets

6x - 4 = 5x + 18

Evaluate the like terms

x = 2

Recall that

∠ABC = ∠ABD

So, we have

∠ABD = 3x - 2

This gives

∠ABD = 3 x 22 - 2

Evaluate

∠ABD = 64

Hence, the angle is 64 degrees