Answer:
1) H0: μ₁=μ₂ against the claim Ha: μ₁ ≠μ₂
2)The test statistic is
t= x1`-x2`/ Sp √ ( 1/n₁ + 1/n₂)
where
Sp= s₁² ( n1-1) + s₂²(n2-1) /(n1-1) + (n2-1)
3) D.f= n1+n2-2= 32+28-2= 58
Step-by-step explanation:
The null hypothesis is that there is no difference in population means (masterâs degree minus bachelorâs degree)
The claim is that there there is a difference in population means (masterâs degree minus bachelorâs degree)
1) H0: μ₁=μ₂ against the claim Ha: μ₁ ≠μ₂
2)The test statistic is
t= x1`-x2`/ Sp √ ( 1/n₁ + 1/n₂)
where
Sp= s₁² ( n1-1) + s₂²(n2-1) /(n1-1) + (n2-1)
Putting the values
Sp= 12,250,000( 31) + 16,000,000(27)/ 31+27
Sp= 379,750,000- 432,000,000/58
Sp= -52,250,000/58
Sp= -900,862.1
Now Putting the values in the t- test
t= x1`-x2`/ Sp √ ( 1/n₁ + 1/n₂)
t= 55,000- 58,000/ -900,862.1 √1/32+ 1/28)
t= -3000/ -233,120.21
t= 0.012868
3) D.f= n1+n2-2= 32+28-2= 58
for 2 tailed test the critical value of t is obtained by
t≥ t∝/2 ( d.f)=t≥ t0.025 (58)= ± 2.0017
4) Since the calculated value of t= 0.012868 does not fall in the critical region t≥ t∝/2 ( d.f)= ± 2.0017 we conclude that H0 is true and accept the null hypothesis.
