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zalisa [80]
3 years ago
14

The area of a rectangle is 48ft2. The length is 3 times the width. Which of the following equations can be used to solve for the

width?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

Width of rectangle = 4 ft

Step-by-step explanation:

Given:

Area of rectangle = 48 ft²

Length of rectangle = 3[Width of rectangle]

Find:

Width of rectangle

Computation:

Assume;

Width of rectangle = a

So,

Length of rectangle = 3[Width of rectangle]

Length of rectangle = 3a

Area of rectangle = l x b

48 = 3a x a

3a² = 48

a² = 16

a = 4

Width of rectangle = 4 ft

Length of rectangle = 3[Width of rectangle]

Length of rectangle = 3[4]

Length of rectangle = 12 ft

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Answer: 0.1353

Step-by-step explanation:

Given : The mean of failures =  0.025 per hour.

Then  for 8 hours , the mean of failures = \lambda=8\times0.25=2 per eight hours.

Let X be the number of failures.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that the instrument does not fail in an 8-hour shift :-

P(X=0)=\dfrac{e^{-2}2^0}{0!}=0.1353352\approx0.1353

Hence, the the probability that the instrument does not fail in an 8-hour shift = 0.1353

7 0
3 years ago
Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

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a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

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a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

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Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

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Learn more here:

brainly.com/question/2962546

4 0
3 years ago
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Answer:

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AB is a midsegment.

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