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2 years ago

Suppose f"(x) = -9 sin(3x) and f'(0) = -4, and f(0) = -2 Find f(pi/4)

Mathematics

1 answer:

grigory [225]2 years ago

5 0

Answer:

9sin (3)and f,(0)=4,AND f(0)=2

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Answer:

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37734 35202 2532

45299 41635 3664

36240 35500 740

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38200 37810 390

33500 33215 285

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Mean = $d=939.5$

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$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

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c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

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So, $t_{\frac{\alpha}{2}}=3.499$

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confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

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Answer:

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