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Olenka [21]
3 years ago
13

--

Mathematics
1 answer:
lara [203]3 years ago
5 0
21 I hope this helps :)
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7 yd<br> 4 yd<br> 18 yd<br> 11 yd<br> 14 yd
Dima020 [189]

Answer:

????????????

Step-by-step explanation:

8 0
3 years ago
-3(1-2x)-3=-20-8x what is the work and answer
larisa86 [58]
You have to keep order of operations in mind.

1. Take care of the parentheses; distribute.
-3+6x-3=-20-8x
Simplified: 6x-6=-20-8x

2. Isolate the x variable.
Add 8x to both sides and add 6 to both sides.
14x=-14

3. Solve for x.
Divide by 14 on both sides.
x=-1
4 0
3 years ago
Question in the image below:
horrorfan [7]

Answer:

x = 5/33 or 0.151515151

Step-by-step explanation:

7(-6x-2) = 8(3x-4)

step 1: simplify the equation.

-42x - 14 = 24x - 4

step 2: isolate the variable (using the balance method).

-42x - 14 + 14 = 24x - 4 + 14

-42x = 24x + 10

-42x - 24x = 24x - 24x + 10

-66x = 10

step 3: solve for x.

x = 10 ÷ -66

x = 5/33

4 0
2 years ago
Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro
Elanso [62]

Answer:

<em>Choose the first alternative</em>

\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions (N_s) and the total number of possible choices (N_t), i.e.

\displaystyle P=\frac{N_s}{N_t}

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}

The total number of possible choices is

_{2}^{20}\textrm{C} \text{ ways to do it}

The probability is then

\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}

Choose the first alternative

7 0
3 years ago
Read 2 more answers
A bakery sells ,medium and large pies. The ratio small:medium:large is 3:5:2 .What fraction of the pies are large ?
SOVA2 [1]
2/8

there’s 8 total pies and among all of them, there’s only 2 large pies
so 2 large pies out of eight pies
6 0
2 years ago
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