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Rama09 [41]
3 years ago
15

2. A train first travels east for 20 kilometers. Then it turns north and travels for 43 kilometers. Next it goes west for 20 kil

ometers. Finally, it travels south for an unknown number of kilometers. At the end of the journey, the train is back at the original location. How far did it travel southward?​
Mathematics
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

idk sorry

Step-by-step explanation:

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Hey can you please help me posted picture of question
Rudik [331]
Answer:
f⁻¹(x) = \frac{7x-3}{4}

Explanation:
To get the inverse of a function, we have to follow these steps:
1- replace f(x) with y
2- swap the x and y variables
3- solve for y
4- replace y with f⁻¹(x)

Applying this to the given as follows:
f(x) = \frac{4x-3}{7}

Step 1: replace f(x) with y:
y = \frac{4x-3}{7}

Step 2: swap the x and y variables:
x = \frac{4y-3}{7}

Step 3: solve for y:
7x = 4y - 3
4y = 7x - 3
y = \frac{7x-3}{4}

Step 4: replace y with f⁻¹(x):
f⁻¹(x) = \frac{7x-3}{4}

Hope this helps :)
8 0
4 years ago
in Youngstown, the population reached 4420 people in 1993. in 1998 the population was 5600 residents. what was the population in
Julli [10]
5600 - 4420 = 1180....so there is a difference of 1180 in a period of (1998 - 1993) = 5 yrs.

1180/5 = 236 people per yr

so in 1998 the population was 5600.....in 2000 (2 yrs later) the population would be : 5600 + 236(2) = 5600 + 472 = 6072 <==
4 0
4 years ago
Solve the following equations for x,
stellarik [79]

(i) 3 csc²(<em>x</em>) - 4 = 0

3 csc²(<em>x</em>) = 4

csc²(<em>x</em>) = 4/3

sin²(<em>x</em>) = 3/4

sin(<em>x</em>) = ± √3/2

<em>x</em> = arcsin(√3/2) + 2<em>nπ</em>  <u>or</u>   <em>x</em> = arcsin(-√3/2) + 2<em>nπ</em>

<em>x</em> = <em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   <em>x</em> = -<em>π</em>/3 + 2<em>nπ</em>

where <em>n</em> is any integer. The general result follows from the fact that sin(<em>x</em>) is 2<em>π</em>-periodic.

In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, the first family of solutions gives <em>x</em> = <em>π</em>/3 and <em>x</em> = 4<em>π</em>/3 for <em>n</em> = 0 and <em>n</em> = 1, respectively; the second family gives <em>x</em> = 2<em>π</em>/3 and <em>x</em> = 5<em>π</em>/3 for <em>n</em> = 1 and <em>n</em> = 2.

(ii) 4 cos²(<em>x</em>) + 2 cos(<em>x</em>) - 2 = 0

2 cos²(<em>x</em>) + cos(<em>x</em>) - 1 = 0

(2 cos(<em>x</em>) - 1) (cos(<em>x</em>) + 1) = 0

2 cos(<em>x</em>) - 1 = 0   <u>or</u>   cos(<em>x</em>) + 1 = 0

2 cos(<em>x</em>) = 1   <u>or</u>   cos(<em>x</em>) = -1

cos(<em>x</em>) = 1/2   <u>or</u>   cos(<em>x</em>) = -1

[<em>x</em> = arccos(1/2) + 2<em>nπ</em>   <u>or</u>   <em>x</em> = 2<em>π</em> - arccos(1/2) + 2<em>nπ</em>]   <u>or</u>   <em>x</em> = arccos(-1) + 2<em>nπ</em>

[<em>x</em> = <em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   <em>x</em> = 5<em>π</em>/3 + 2<em>nπ</em>]   <u>or</u>   <em>x</em> = <em>π</em> + 2<em>nπ</em>

For 0 ≤ <em>x</em> ≤ 2<em>π</em>, the solutions are <em>x</em> = <em>π</em>/3, <em>x</em> = 5<em>π</em>/3, and <em>x</em> = <em>π</em>.

7 0
3 years ago
What is the sum of the first five terms of a geometric series with a1=20 and r=1/4
IrinaK [193]
The sum of a geometric sequence is:

s(n)=a(1-r^n)/(1-r), a=initial term and r=common ration so

s(n)=20(1-0.25^n)/(1-0.25)

s(5)=20(1-0.25^5)/(0.75)

s(5)=26.640625
7 0
3 years ago
Read 2 more answers
How do you find missing side lengths for special right triangles?
murzikaleks [220]
By using pythagorian theorem
https://youtu.be/WsjIu4XnOYA
6 0
3 years ago
Read 2 more answers
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