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3 years ago

Which term best completes the digram showing which groups had more power in roman society

Mathematics

2 answers:

Nastasia [14]3 years ago

8 0

I would say C. because the more people they had the more Stronger they were

borishaifa [10]3 years ago

4 0

Answer:

slaves

Step-by-step explanation:

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Which expression is equivalent to 4^-5 • 3^-5 ?

valkas [14]

The expression equivalent to 4^-5 • 3^-5 is 12^-5

<h3>What are equivalent expressions?</h3>

Equivalent expressions are simply known as expressions with the same solution but different arrangement.

Given the index expressions;

4^-5 • 3^-5

Using the exponent rule, the two values are have different bases but the same exponent and thus, we multiply the bases and leave the exponents the same way.

This can be written as;

4(3) ^ -5

expand the bracket

12^-5

Thus, the expression equivalent to 4^-5 • 3^-5 is 12^-5

Learn more about equivalent expressions here:

brainly.com/question/24734894

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7 0

2 years ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$