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shepuryov [24]
3 years ago
10

What is the working principle of computer?​

Computers and Technology
1 answer:
IRINA_888 [86]3 years ago
4 0

Answer:

input, process, output, storage

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Control+A to highlight all text.
Then Control+i will italize the highlighted text.
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Why you should care about copyright
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Copyright protects those words from being used in any form without the author's approval and it can lead to The law provides a range from $200 to $150,000 for each work copyrighted.

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3 years ago
Find the name of the professor with the maximum percentage of students that failed his course.
aleksandrvk [35]

The minimum score needed to make an A is 89.

<h3>What is the z-score?</h3>

A Z Score, also known as the Standard Score, is a calculation used to determine how many standard deviations a raw score is below or above the population mean. Simply said, the Z Score informs you of a value's relationship to the mean and the distance a data point is from the mean.

Since the grades of his students were normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = grades of his students.

µ = mean grade

σ = standard deviation

From the information given,

µ = 74

σ = 10

The professor has informed us that 6.3 percent of his students received A's. The p-value for the minimum score is 1 - 0.063 = 0.937. The z value of 0.937 is 1.53.

1.53 = (x - 74)/10

1.53 × 10 = x - 74

15.3 = x - 74

x = 15.3 + 74

x = 89.3

Therefore, the minimum score needed to make an A is 89.

The complete question is given below:-

A professor at a local community college noted that the grades of his students were normally distributed with a mean of 74 and a standard deviation of 10. The professor has informed us that 6.3 percent of his students received A's while only 2.5 percent of his students failed the course and received F's. What is the minimum score needed to make an A?

To know more about the z- score, follow

brainly.com/question/25638875

#SPJ4

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2 years ago
How many address bits are needed to specify each byte in a 512 byte memory unit?
schepotkina [342]

Explanation:

In a 512 byte memory unit, in order to address each byte, there will be 512 locations (each one byte) ranging from 0 to 511.

Thus it will take 9 bits (2^9=512) to store the address within the unit.

5 0
3 years ago
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