Answer:
I believe its C
Explanation:
I'm sorry if its wrong...
Answer:
lines 2,3 and 5 ( c )
Explanation:
The lines that immediately flush the output buffer are : System.out.print("Two for the show\n"); . System.out.println("Three to get ready"); and System.out.flush();
making use of the new line character or printIn() statement the buffered output gets flushed therefore making autoflush true
but System.out.print() doesn't use any flush technique so we need to flush the buffered output done by the print() statement hence we choose lines 2,3,5
Answer:
if (arr[i] > max) -> max3 = max2, max2 = max , max = arr[i]. else if (arr[i] > max2) -> max3 = max2, max2 = arr[i]. else if (arr[i] > max3) -> max3 = arr[i]. At the end of the loop, we will print all three values.
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Answer:
The correct answer to the following question will be "n logn".
Explanation:
- Time Complexity should be the same as the whole last particular instance, just the log base keeps changing with three.
- Throughout the circumstance of separating 2 arrays, we want one correlation. however, for splitting between 3-way arrays, will require 2 comparisons to sort.
- However, after breaking the array into 3, we can lower the number of transfers by growing the comparison. So the time complexity would then persist the same, but the log should get base 3 as we've classified into different parts.
So the time complexity will be:
⇒ 
⇒ 