24.67 is just barely before 25.00, so we should be able to round 20.00, which gives us only one significant digit.
<h2>Steps</h2>
So for this system, one equation will represent the number of fruit and the other equation will represent the combined total of the fruit. (Let x = apples and y = bananas):
![x+y=20\\0.5x+0.75y=11.50](https://tex.z-dn.net/?f=x%2By%3D20%5C%5C0.5x%2B0.75y%3D11.50)
Next, I will be using the substitution method to remove one of the variables. To do this, firstly subtract both sides by y in the first equation:
![x=20-y\\0.5x+0.75y=11.50](https://tex.z-dn.net/?f=x%3D20-y%5C%5C0.5x%2B0.75y%3D11.50)
Next, since we know that x is equal to 20 - y, substitute it into the second equation and solve for y:
![0.5(20-y)+0.75y=11.50\\10-0.5y+0.75y=11.50\\10+0.25y=11.50\\0.25y=1.50\\y=6](https://tex.z-dn.net/?f=0.5%2820-y%29%2B0.75y%3D11.50%5C%5C10-0.5y%2B0.75y%3D11.50%5C%5C10%2B0.25y%3D11.50%5C%5C0.25y%3D1.50%5C%5Cy%3D6)
Now that we have the value of y, substitute it into either equation to solve for x:
![x+6=20\\x=14\\\\0.5x+0.75(6)=11.50\\0.5x+4.5=11.50\\0.5x=7\\x=14](https://tex.z-dn.net/?f=x%2B6%3D20%5C%5Cx%3D14%5C%5C%5C%5C0.5x%2B0.75%286%29%3D11.50%5C%5C0.5x%2B4.5%3D11.50%5C%5C0.5x%3D7%5C%5Cx%3D14)
<h2>Answer</h2>
<u>In short, Angelo bough 14 apples and 6 bananas.</u>
< A = 40
< B is a complement of < A....so < B = (90 - 40) = 50
< C is a supplement of < B....so < C = (180 - 50) = 130
I believe this would be a triangular prism