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kakasveta [241]
3 years ago
13

Find the equation of the line in slope-intercept form. m=− 4 7 through (14, 3

Mathematics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

The answer to your question is:   y = -47x + 661

Step-by-step explanation:

Data

m = - 47         I wasn't sure if the slope was -47 or -4.

Point (14, 3)

Formula

(y - y1) = m(x - x1)

Process

                  (y - 3) = -47(x - 14)

                   y - 3 = -47x + 658

                   y = -47x + 658 + 3

                   y = -47x + 661

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Answer:

the one solution is -20

Step-by-step explanation:

-15x - 27 + 7 = -25 - 15x +5

-27 + 7 = -25 +5

-20 = -20

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Tamara has money in a savings account
olga2289 [7]

Answer:

  • 1.03a

Step-by-step explanation:

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2. ........................

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4 0
3 years ago
Pls help I have thirty minutes to get this done
Radda [10]

Answer:

1. D

2. F

3. B

4. A

5. A

6. F

Step-by-step explanation:

Solve for X

8 0
2 years ago
11. Little Sally Walker has a choice between going to an in-state college where she would pay
nalin [4]

Answer:

Step-by-step explanation:

Lets calculate first for in state college

yearly tuition fees = $3,500

monthly living expense = $700

one year has 12 months so yearly living expense =$700 * 12 = $8,400

Yearly expense of the in state college = yearly tuition fees ($3,500 )+ yearly living expense($8,400)   = $3,500 + $8,400  = $11,900

____________________________________________________

Lets calculate first for  out of state college

yearly tuition fees = $6,000

monthly living expense = $400

one year has 12 months so yearly living expense =$400 * 12 = $4,800

Yearly expense of the out of state college = yearly tuition fees ($3,500 )+ yearly living expense($8,400)   = $6,000 + $4,800  = $10,800

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3 0
3 years ago
Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

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x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
3 years ago
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