2 years ago

PLEASE HELP ASAP!!!

Mathematics

1 answer:

MAVERICK [17]2 years ago

3 0

Answer:

y - 2, 3, 4, 5

Hope this helps :)

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Multiply. Write your answer in simplest form. 2 1/2 × 3 2/3

Nonamiya [84]

2 1/2 = 5/2
3 2/3 = 11/3
5/2 x 11/3 = 55/6
55/6 = 9 1/6

Hope it helped.

8 0

3 years ago

Name the algebraic property demonstrated in the example below: (1 point) If x = 3 and 3 = y, then x = y.

lubasha [3.4K]

Answer:

Transitive Propertey

Step-by-step explanation:

Because it has "If" in it.

5 0

4 years ago

Sarah used 3.25 meters of fabric to make a costume. How many centimeters of fabric did she use?

igor_vitrenko [27]

Answer:

325 centimeters

Step-by-step explanation:

5 0

3 years ago

Evaluate the surface integral. s x ds, s is the triangular region with vertices (1, 0, 0), (0, −2, 0), and (0, 0, 12).

aniked [119]

Parameterize the surface by

$\mathbf r(s,t)=(1-s)(0,0,12)+s\bigg((1-t)(1,0,0)+t(0,-2,0)\bigg)$
$\implies\mathbf r(s,t)=(x(s,t),y(s,t),z(s,t))=(s-st,-2st,12-12s)$

where $(s,t)\in(0,1)\times(0,1)$ . We have

$\|\mathbf r_s\times\mathbf r_t\|=\|(1-t,-2t,-12)\times(-s,-2s,0)\|=2\sqrt{181}s$

The surface integral is then

$\displaystyle\iint_Sx\,\mathrm dS=2\sqrt{181}\int_{s=0}^{s=1}\int_{t=0}^{t=1}s(s-st)\,\mathrm dt\,\mathrm ds$
$=\displaystyle2\sqrt{181}\left(\int_{s=0}^{s=1}s^2\,\mathrm ds\right)\left(\int_{t=0}^{t=1}(1-t)\,\mathrm dt\right)$
$=\dfrac{\sqrt{181}}3$

7 0

3 years ago

When asked to rewrite the expression (x3 + 2x? – x)-(-x3 + 2x2 + 6), Denise made a mistake. She did not get the correct answer,

DanielleElmas [232]

Answer:

She rewrote the problem without parentheses: x3+ 2x2 - x + x3 – 2x2 +6

Step-by-step explanation:

It looks like she didn't fully distribute the -

(x3 + 2x2 - x)-(-x3 + 2x2 + 6) :Original

x3+ 2x2 - x + x3 – 2x2 +6 :Changed

(x3 + 2x2 - x)-(-x3 + 2x2 + 6)

x3 + 2x2 - x + x3 - 2x2 - 6

x3 + x3 + 2x2 - 2x2 -x - 6

2x3-x-6

I hope this helps ^-^

3 0

3 years ago