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kipiarov [429]
2 years ago
15

Which sample is biased?

Mathematics
1 answer:
egoroff_w [7]2 years ago
5 0

Answer: Was there supposed to be a picture?

Step-by-step explanation:

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Answer of u know pleaseee
wlad13 [49]

Answer:

C

Step-by-step explanation:

(10 1/3)/(2/3) = 15.5

15.5 * 6 = 93

5 0
2 years ago
How would I solve this equation?
sergiy2304 [10]

Let's solve your equation step-by-step.<span><span><span>
2/3</span><span>(<span><span>3x</span>+1</span>)</span></span>=5</span>
Step 1: Simplify both sides of the equation.<span><span><span>
2/3</span><span>(<span><span>3x</span>+1</span>)</span></span>=5</span><span>
Simplify: (Show steps)</span><span><span><span>
2x</span>+<span>2/3</span></span>=5</span>
Step 2: Subtract 2/3 from both sides.<span><span><span><span>
2x</span>+<span>2/3</span></span>−<span>2/3</span></span>=<span>5−<span>2/3</span></span></span><span><span>
2x</span>=<span>13/3</span></span>
Step 3: Divide both sides by 2.<span><span><span>
2x/</span>2</span>=<span><span>13/3/</span>2</span></span><span>
x=<span>13/6</span></span>
Answer:<span>
x=<span>13/<span>6</span></span></span>
8 0
3 years ago
Read 2 more answers
What is the difference? StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction Sta
katovenus [111]

Answer:

The option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is \frac{-2(x+6)}{(x+4)(x-4)}

Therefore \frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}

Step-by-step explanation:

Given problem is StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction

It can be written as below :

\frac{x}{x^2-16}-\frac{3}{x-4}

To solve the given expression

\frac{x}{x^2-16}-\frac{3}{x-4}

=\frac{x}{x^2-4^2}-\frac{3}{x-4}

=\frac{x}{(x+4)(x-4)}-\frac{3}{x-4}  ( using the property a^2-b^2=(a+b)(a-b) )

=\frac{x-3(x+4)}{(x+4)(x-4)}

=\frac{x-3x-12}{(x+4)(x-4)} ( by using distributive property )

=\frac{-2x-12}{(x+4)(x-4)}

=\frac{-2(x+6)}{(x+4)(x-4)}

\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}

Therefore \frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}

Therefore the option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is \frac{-2(x+6)}{(x+4)(x-4)}

5 0
3 years ago
Read 2 more answers
What is this number in expanded form?
rodikova [14]

Answer:

100,000 + 30,000 + 900 + 80 + 7

(Brainliest please! :D)

5 0
3 years ago
Read 2 more answers
Find the value of x.<br> 1) m_2 = 3x + 13<br><br> y’all please help
natali 33 [55]

Answer:

x-- 3

Step-by-step explanation:

3 0
3 years ago
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