The fish tank was $50 yesterday, and today it has gone up by 25%... What's the new price?
1 answer:
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Answer:
Step-by-step explanation:
Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).
- Brown:
- Yellow or Blue:
....add the numerators
- Not Green:
.... since the sum of all the rest is 80%
- Stiped:
.... there are 0 striped candies.
Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.
- 3 Browns:
- the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.
- None are Yellow: multiply the percent of all minus yellow three times.
- At least 1 green: multiply the percent of green by 100% twice, since the other two can by any
Answer:
Hence the maximum possible volume will be the 778.53 c.c
Step-by-step explanation:
Given:
A rectangle with 13 x 26 dimensions
And corners are cut to form side squares.
To Find:
Maximum possible volume for box
Solution :
Consider a rectangle of 13 x 26 dimension with and side of square at corner be x.
(Refer the attachment)
Now,
Formulating the volume equation for the box
So corner square sides we are going to fold up which makes height of the box
and remaining part will be length and breadth
As shown in fig,
Length=26-x
breadth=13-x
And height will be x
To get maximum volume differentiate the above equation,
Now ,Solve the Quadratic Equation to get x values,
=0
x=[-b±(b^2-4ac)^1/2]/2a
x=[78±Sqrt[(78)^2-4*338*3)]/2*3
x=[78±Sqrt(3028)]/6
x=[78±55.027]/6
x=78+55.027/6 or x=78-55.027/6
x=22.17 or x=3.8288
Use these values in 6x-78 to know which value posses the max and min value for the function.
So when x=22.17
6x-78=6*22.17-78
=55.02>0 i.e function will have minimum value .
When x=3.8288
6*3.8288-78
=-55.0272<0 i.e. Function will have maximum value
Now, the function will defines the maximum volume
